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ser-zykov [4K]
2 years ago
10

Explain how water is controlled to generate electrical energy in hydro-electric dams. and show a diagram is help explain the ans

wer.
Physics
1 answer:
kirza4 [7]2 years ago
6 0
Here is how I would I explain it. Water is channeled through tunnels in the dam. The energy of water flowing through the dam’s tunnels cause turbines to turn. The turbines make generators move. Generators are machines that produce electricity. Engineers control the amount of water let through the dam. The process used to control this flow of water is called the intake system.

Hope this helps can’t do the diagram part.
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A long wire carries a current 5 A from west to east. A magnetic compass pointing North is placed underneath the wire at a distan
Gemiola [76]

Answer:

no deflection

Explanation:

current is flowing from west to east. As the magnetic field of a long wire carrying current is circular, its direction will be north below the wire and south above the wire (according to the right hand rule). So, when the compass is placed underneath the wire, it will still point towards the north direction.

6 0
3 years ago
The Achilles tendon connects the muscles in your calf to the back of your foot. When you are sprinting, your Achilles tendon alt
drek231 [11]

Answer:

5 mm

Explanation:

Youngs's modulus (Y) is described by the following expression:

Y=\frac{F*L}{\Delta L*A}

Where F is the force exerted on the tendon, L is its length, A is its area and ΔL is its change in length (stretching).

The force in this case is 8 times the weight of the runner:

F= 8*m*g\\F= 8*70*9.8\\F=5488 N

Therefore, the change in length of the tendon is given by:

\Delta L=\frac{F*L}{Y*A}\\\Delta L=\frac{5488*0.15}{0.15*10^{10}*1.1*10^{-4}}\\\Delta L= 0.004989 m

the runner's Achilles tendon will stretch by 0.004989 m, which is roughly 5 mm.

8 0
4 years ago
What is the fundamental source of all energy in the universe ?
Ulleksa [173]
The energy from the sun is what sustains the solar system. But this is only a small part of the universe. So it will be inaccurate to say that the source of all energy in the universe is the sun. 
<span>The universe is made up of several other galaxies including our own milky way. But looking at these components of the universe, they are made up of stars. Considering that all other stars are similar to our sun, which by the way is also a star, then we can put it that their collective energies is what constitutes the energy source for the universe. </span>
<span>But here we have only considered what we know about the universe, since man has been able to explore only a minute fraction of the universe, it wont be fair to argue that this is absolute. There may be other energy sources out there that have not yet been discovered, but for now, the idea behind the summation of celestial energies should suffice. </span>
3 0
3 years ago
At what speed must a 0.6 kg stone be thrown in order that it has a relativistic mass of 0.76 kg? (c = 3.00 x 10^8 m/s) A) 0.6976
soldier1979 [14.2K]

Answer:

The speed of the stone is 0.6138 c.

(B) is correct option.

Explanation:

Given that,

Mass of stone m= 0.6

Relativistic mass = 0.76

We need to calculate the speed

Using formula of rest mass

m_{r}=\dfrac{m_{0}}{\sqrt{1-\dfrac{v^2}{c^2}}}

v^2=(\dfrac{m_{0}^2}{m_{r}^2}-1)c^2

Put the value into the formula

v^2=(\dfrac{0.6^2}{0.76^2}-1)\times c^2

v=\sqrt{0.37673c^2}

v=0.6138c

Hence, The speed of the stone is 0.6138 c.

3 0
3 years ago
The current theory of the structure of the
irina1246 [14]

Answer:

pt 1: m=1.66698*10^{21} kg

Pt 2: KE=1212.23531 J

Explanation:

Information Given: (p = density)

l = 5200km  d = 35km p = 2700kg/m^{2}

Part 1: Mass

  • Find volume
  1. V=(l)^2(d)
  2. V=(4.2*10^6)^2(35*10^3)
  3. V=61.74*10^{16}
  • Find Mass
  1. m=Vp
  2. m=(61.74*10^{16})(2700)
  3. m=1.66698*10^{21}

Part 2: Kinetic Energy

  1. v=\frac{3.8cm}{yr}*\frac{m}{100cm}*\frac{yr}{365d}*\frac{d}{24hr}*\frac{hr}{3600s}
  2. v=1.20497*10^{-9}

KE=\frac{1}{2}mv^2

KE=\frac{1}{2} (1.66698*10^{21})(1.20497*10^{-9})^2

KE=1212.23531 J

Part 3: Jogger Speed

set up, because I don't have the mass :(

Information given:

KE_{jogger}

  1. KE=\frac{1}{2}mv^2
  2. v_{jogger} =\sqrt{\frac{2KE}{m_{jogger} } }
  • Input the values

Hope it helps :)

6 0
3 years ago
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