When ΔG° is the change in Gibbs free energy
So according to ΔG° formula:
ΔG° = - R*T*(㏑K)
here when K = [NH3]^2/[N2][H2]^3 = Kc
and Kc = 9
and when T is the temperature in Kelvin = 350 + 273 = 623 K
and R is the universal gas constant = 8.314 1/mol.K
So by substitution in ΔG° formula:
∴ ΔG° = - 8.314 1/ mol.K * 623 K *㏑(9)
= - 4536
Answer:
Compound 1 is molecular
Compound 2 is ionic
Compound 3 can't really be decided
Explanation:
A molecular substance does not conduct electricity, has very low melting and boiling points and is held together by very weak intermolecular forces.
An ionic substance conducts electricity in solution or in molten state but never in the pure solid state, has a high melting and boiling point and has a dull appearance most times.
Compounds 1 shows the properties of molecular substances hence it are designated as such.
On the other hand, compound 2 shows the properties of an ionic substance and is also designated as such.
We can't really decide on compound 3 because it shows some properties of ionic substances and some properties of molecular substances.
This is all no chemistry but the answer is C
Answer:
1: energy
2: converts
Kinetic energy is either 3 or 4, those questions are really similar.
<span>The equation you used is KE=hv-hv0, where h=6.63*10^-34 (constant). You multiply h by 1.5*10^15. Multiply h by the threshold freq of cesium (from part A). Subtract the second answer from the first answer, and you get the kinetic energy. Hope this helps.</span>
