<u>Given:</u>
The initial energy of the electron Einitial = 16.32 * 10⁻¹⁹ J
The energy released i.e the change in energy ΔE = 5.4 * 10⁻¹⁹ J
<u>To determine:</u>
The final energy state Efinal of the electron
<u>Explanation:</u>
Since energy is being released, this suggests that Efinal < Einitial
i.e. ΔE = Einitial - Efinal
Efinal = Einitial - ΔE = (16.32 - 5.4)*10⁻¹⁹ = 10.92 * 10⁻¹⁹ J
Ans: A)
The electron moved down to an energy level and has an energy of 10.92 * 10⁻¹⁹ J
Answer C is for kg and but it's .00134 for grams
In all atoms, the number of protons and the number of electrons is always the same. The number of neutrons is very roughly the same as the number of protons, but sometimes it's rather more. The number of protons in an atom is called the atomic number and it tells you what type of atom you have.
Answer:
Firstly, We have to convert it in the Miles formula...
No. of moles = Mass given/Molar Mass
So, the final answer be come<em> </em>
<h3><em><u> </u></em><em><u>Ans</u></em><em><u> </u></em><em><u>-</u></em><em><u> </u></em><em><u>5</u></em><em><u>0</u></em><em><u>.</u></em><em><u>8</u></em><em><u> </u></em><em><u>gm</u></em><em><u> </u></em><em><u>and</u></em><em><u> </u></em><em><u>there</u></em><em><u> </u></em><em><u>same</u></em><em><u> </u></em><em><u>%</u></em><em><u> </u></em><em><u>is</u></em><em><u> </u></em><em><u>5</u></em><em><u>0</u></em><em><u>.</u></em><em><u>8</u></em><em><u>%</u></em><em><u> </u></em><em><u>butane</u></em><em><u> </u></em><em><u>in</u></em><em><u> </u></em><em><u>react</u></em><em><u>ion</u></em><em><u> </u></em></h3>
Answer:
(a) 
(b) Rubidium
Explanation:
Hello,
This titration is carried out by assuming that the volume of base doesn't have a significant change when the mass is added, thus, we state the following data a apply the down below formula to compute the molarity of the base solution:

Solving for the molarity of base we've got:

Now, we can compute the moles of the base as:

(a) Now, one divides the provided mass over the previously computed moles to get the molecular mass of the unknown base:

(b) Subtracting the atomic mass of oxygen and hydrogen, the metal's atomic mass turns out into:

So, that atomic mass dovetails to the Rubidium's atomic mass.
Best regards.