All categories

3 years ago

A. What chemicals are involved in the formation of acid rain? What are the sources of these chemicals? (2 points)

Chemistry

1 answer:

lesya692 [45]3 years ago

6 0

Answer:

See explanation

Explanation:

The to main chemicals that lead to acid rain are SOx and NOx. The major source of oxides of sulphur are power plants while the major source of oxides of nitrogen is the combustion of fossil fuels.

B. There are two types of acid rain; wet and dry. Wet type acid rain occurs when NOx and SOx combine with water vapour in the atmosphere and fall as precipitation while in dry type, wind deposits these acidic gases/matter on the surfaces of buildings, cars, trees etc. Rain water washes off these acidic deposits and the runoff is more acidic than the rain water.

C. Natural rain water has a pH of about 5.5 due to the fact that water dissolve CO2 in the atmosphere. This means that natural rain water is also slightly acidic. Rain water that dissolves SOx or NOx is often more acidic than these hence the term 'enhanced acid rain' may be used.

Again, since precipitation could be solid or liquid, the term 'acid deposition' is better.

You might be interested in

Two children on a seesaw are able to balance perfectly while on Earth.would they still be balanced if you saw was brought to the

Setler [38]

Answer:

Explanation:

Because on the moon you are basically weightless and your mass would stay the same

3 0

3 years ago

The reaction below demonstrates which characteristic of a base?

svlad2 [7]

Answer: option D. the ability of a base to react with a soluble metal salt.

Justification:

NaOH is a strong base, which means that in water it will dissociate according to this reaction:

NaOH(aq) → Na⁺ (aq) + OH⁻ (aq)

On the other hand, CuSO₄ is a soluble ionic salt which in water will dissociate into its ions according to this other reaction:

CuSO₄(aq) → Cu²⁺ + SO₄²⁻

Hence, in solution, the sodium ion (Na⁺) will react with the metal salt in a double replacement reaction, where the highly reactive sodium ion (Na⁺) will substitute the Cu²⁺ in the CuSO₄ to form the sodium sulfate salt, Na₂SO₄ (water soluble), and the copper(II) hydroxide, Cu(OH)₂ (insoluble).

That is what the given reaction represents:

CuSO₄ (aq) + 2NaOH(aq) → Cu(OH)₂(s) + Na₂SO₄(aq)

↑ ↑ ↑ ↑

soluble metal salt strong base insoluble base solube salt

5 0

3 years ago

Read 2 more answers

1. Chemical equilibrium is established when the number of reactants equals the number of products.. . - True. - False. . 2. Acco

torisob [31]

1)false a in chemical equilibrium concentration of reactant is equal to concentration of product
2)as here they said heat is added in product side means its endothermic reaction and in endothermic reaction on increasing temp. equilibrium shift towards forward direction so its true
3) B)as here mole are equal in reactant and product side that is 2 and if we increase pressure equilibrium shift in dat direction where no. of moles are less and here mole are equal so it will remain unaffected

7 0

3 years ago

Read 2 more answers

What should you do if the high power objective lens touches or breaks the cover slip?

saul85 [17]

Tell your teacher. They'll know what to do and it's best to report it to them.

6 0

3 years ago

Which aqueous solution has the highest boiling point at standard pressure?(1) 1.0 M KC1(aq) (3) 2.0 M KCl(aq)(2) 1.0 M CaC12(aq)

miss Akunina [59]

Answer:

(4) 2.0 M CaCl₂(aq).

Explanation:

Adding solute to water elevates the boiling point.

The elevation in boiling point (ΔTb) can be calculated using the relation:

ΔTb = i.Kb.m,

where, ΔTb is the elevation in boiling point.

i is the van 't Hoff factor.

van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.

Kb is the molal elevation constant of water.

m is the molality of the solution.

(1) 1.0 M KCl(aq):

i for KCl = no. of particles produced when the substance is dissolved/no. of original particle = 2/1 = 2.

suppose molarity = molality, m = 1.0 m,

∴ ΔTb for (1.0 M KCl) = i.Kb.m = (2)(Kb)(1.0 m) = 2(Kb).

(2) 2.0 M KCl(aq):

i for KCl = no. of particles produced when the substance is dissolved/no. of original particle = 2/1 = 2.

suppose molarity = molality, m = 2.0 m,

∴ ΔTb for (1.0 M KCl) = i.Kb.m = (2)(Kb)(2.0 m) = 4(Kb).

(3) 1.0 M CaCl₂(aq):

i for CaCl₂ = no. of particles produced when the substance is dissolved/no. of original particle = 3/1 = 3.

suppose molarity = molality, m = 1.0 m,

∴ ΔTb for (1.0 M KCl) = i.Kb.m = (3)(Kb)(1.0 m) = 3(Kb).

(4) 2.0 M CaCl₂(aq):

i for CaCl₂ = no. of particles produced when the substance is dissolved/no. of original particle = 3/1 = 3.

suppose molarity = molality, m = 2.0 m,

∴ ΔTb for (1.0 M KCl) = i.Kb.m = (3)(Kb)(2.0 m) = 6(Kb).

So, the aqueous solution has the highest boiling point at standard pressure is: (4) 2.0 M CaCl₂(aq).

6 0

3 years ago