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yawa3891 [41]
3 years ago
7

A. What chemicals are involved in the formation of acid rain? What are the sources of these chemicals? (2 points)

Chemistry
1 answer:
lesya692 [45]3 years ago
6 0

Answer:

See explanation

Explanation:

The to main chemicals that lead to acid rain are SOx and NOx. The major source of oxides of sulphur are power plants while the major source of oxides of nitrogen is the combustion of fossil fuels.

B. There are two types of acid rain; wet and dry. Wet type acid rain occurs when NOx and SOx combine with water vapour in the atmosphere and fall as precipitation while in dry type, wind deposits these acidic gases/matter on the surfaces of buildings, cars, trees etc. Rain water washes off these acidic deposits and the runoff is more acidic than the rain water.

C. Natural rain water has a pH of about 5.5 due to the fact that water dissolve CO2 in the atmosphere. This means that natural rain water is also slightly acidic. Rain water that dissolves SOx or NOx is often more acidic than these hence the term 'enhanced acid rain' may be used.

Again, since precipitation could be solid or liquid, the term 'acid deposition' is better.

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What kind of scientist would study the the first of a car running
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Answer:

A physicist

Explanation:

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7 0
3 years ago
A 50.0 mg sample of iodine-131 was placed in a container 32.4 days ago. if its half-life is 8.1 days, how many milligrams of iod
sertanlavr [38]

3.124mg of I-131 is present after 32.4 days.

The 131 I isotope emits radiation and particles and has an 8-day half-life. Orally administered, it concentrates in the thyroid, where the thyroid gland is destroyed by the particles.

What is Half life?

The time required for half of something to undergo a process: such as. a : the time required for half of the atoms of a radioactive substance to become disintegrated.

Half of the iodine-131 will still be present after 8.1 days.

The amount of iodine-131 will again be halved after 8.1 additional days, for a total of 8.1+8.1=16.2 days, reaching (1/2)(1/2)=1/4 of the initial amount.

The quantity of iodine-131 will again be halved after 8.1 more days, for a total of 16.2+8.1+8.1=32.4 days, to (1/4)(1/2)(1/2)=1/16 of the initial quantity.

If the original dose of iodine-131 was 50mg, the residual dose will be (50mg)*(1/16)=3.124mg after 32.4 days.

Learn more about the Half life of radioactie element with the help of the given link:

brainly.com/question/27891343

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7 0
1 year ago
The Paris Agreement intends to direct money toward limiting climate change and lowering greenhouse gas levels. Which groups are
yan [13]
I think the answer it’s e
7 0
4 years ago
Read 2 more answers
If an electron fell to a lower orbit or energy level, energy would be
arsen [322]
It would emit energy in most of the cases in form of light
5 0
4 years ago
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What volume (in liters) does 3.91 moles of nitrogen gas at 5.35 atm and 323 K occupy
daser333 [38]
Moles   =  n  = 3.91 mol

                  Pressure  =  P  =  5.35 atm

                  Temperature  =  T  =  323 K

                  Volume  =  V  =  ?

Formula used: Ideal Gas Equation is used,

                                        P V  = n R  T
Solving for V,
                                           V  =  n R T / P
Putting Values,
                           V  =  (3.91 mol × 0.0825 atm.L.mol⁻¹.K⁻¹ × 323 K) ÷ 5.35 atm

                         V  =  19.36 L

5 0
3 years ago
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