Observation made when lead oxide passes through hydrogen gas
1 answer:
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Answer:
Explanation:
The movement of the electrons is illustrated in the picture attached to this answer. It is a four-step reaction mechanism.
First STEP: The first step involves the transfer of an electron from sodium to form a radical anion.
Second STEP: This radical anion then removes a proton/hydrogen from ammonia in a bid to neutralize itself (hence the hydrogen becomes bonded to the anion).
Third STEP: The sodium (from NaNH₂ formed) transfers an electron again to produce a vinyl carbanion.
Fourth STEP: The carbanion then removes a proton/hydrogen from ammonia (like in the second step) to form a neutral trans-alkene.
NOTE: The circled numbers denote each step while the mechanism on the left represents the use of any alkyl group (R and R') while the mechanism on the right assumes both alkyl groups are methyl. Hence, 2-butyne started the reaction and the final product was trans-2-butene.
Answer : The shape of the fluoroform molecule is Tetrahedral.
Explanation :
First we have to calculate the Hybridization of the molecule by formula,
where,
V = Number of valence shell electron in central atom
H = Number of neighboring monovalent atom
C = charge of cation
A = charge of anion
The central atom in this molecule is Carbon, it has 4 electrons in their valence shell.
The neighboring monovalent atoms are one Hydrogen atom and three Fluorine atom.
There is no charge of cation and anion on the given molecule.
V = 4
H = 1 Hydrogen atom + 3 fluorine atom = 4
C = 0
A = 0
By the above hybridization formula, we get
= 4
The number of electron pair = 4
The number of lone pair = 0
The number of electrons is 4, this means that the hybridization is and the geometry of the molecule is Tetrahedral.
The geometry of the molecule is shown below.
