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Lilit [14]
4 years ago
11

Alkynes are reduced to trans alkenes by a process called dissolving metal reduction. The reaction uses sodium or lithium metal a

s the reducing agent and liquid ammonia as the solvent. The method is specific in the formation of trans alkenes from alkynes. The method involves two successive transfers of single electrons from the alkali metal to the triple bond, with abstraction of protons from the ammonia solvent.Draw curved arrows to show the movement of electrons in this step of the mechanism.Arrow-pushing Instructions

Chemistry
1 answer:
NISA [10]4 years ago
6 0

Answer:

Explanation:

The movement of the electrons is illustrated in the picture attached to this answer. It is a four-step reaction mechanism.

First STEP: The first step involves the transfer of an electron from sodium to form a radical anion.

Second STEP: This radical anion then removes a proton/hydrogen from ammonia in a bid to neutralize itself (hence the hydrogen becomes bonded to the anion).

Third STEP: The sodium (from NaNH₂ formed) transfers an electron again to produce a vinyl carbanion.

Fourth STEP: The carbanion then removes a proton/hydrogen from ammonia (like in the second step) to form a neutral trans-alkene.

NOTE: The circled numbers denote each step while the mechanism on the left represents the use of any alkyl group (R and R') while the mechanism on the right assumes both alkyl groups are methyl. Hence, 2-butyne started the reaction and the final product was trans-2-butene.

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JulijaS [17]

Answer:

1.35\times 10^{-4} M was the concentration of the original solution.

Explanation:

M_1V_1=M_2V_2  (Dilution)

where,

M_1\text{ and }V_1 are molarity and volume of non diluted sample.

M_2\text{ and }V_2 are molarity and volume of diluted sample.

M_1=?

V_1=100.0 \mu L=0.1 mL

(1μL=0.001  mL)

M_2=6.41\times 10^{-6} M

V_2=2.00 mL + 100.0 \mu L=2.00 mL+0.1 mL=2.1 mL

Substituting all values :

M_1\times 0.1 mL=6.41\times 10^{-6} M\times 2.1 mL

M_1=\frac{6.41\times 10^{-6} M\times 2.1 mL}{0.1 mL}=1.35\times 10^{-4} M

1.35\times 10^{-4} M was the concentration of the original solution.

5 0
3 years ago
How many significant figures are in 675000 m <br> 6<br> 4<br> 3<br> 5
Dima020 [189]

Answer:

There are 3 significant figures in 675000

Explanation:

The rules for significant figures:

- Non zero digit (from 1 upward) are always significant

- Trailing zero are not significant

- but zero in the presence of decimal are significant

In this case, the trailing zeros are not significant thus only the first 3 non zero digit are significant.  

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Answer:

A for sure

Explanation:

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3 years ago
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Water’s heat of vaporization is 2,257 joules/gram. How much energy is released when 11.2 grams of water vapor condenses into liq
atroni [7]

Heat of vaporization is the heat required to vaporize unit mass of a substance at it's boiling point. The heat of vaporization or condensation of water is 2257 J/g.

It means that 1 g of water involves 2257 J energy during condensation or vaporization at its boiling point (100 C)

Given mass of water vapor that is condensing = 11.2 g

Calculating the heat released when 11.2 g of water vapor condenses in to liquid water at 100^{0}C:

11.2 g *2257\frac{J}{g} = 25,278 J

Rounding the final answer 25,278 J to three significant figures we get, 25,300 J

Therefore the correct answer is E.  25,300 J


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