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Lilit [14]
3 years ago
11

Alkynes are reduced to trans alkenes by a process called dissolving metal reduction. The reaction uses sodium or lithium metal a

s the reducing agent and liquid ammonia as the solvent. The method is specific in the formation of trans alkenes from alkynes. The method involves two successive transfers of single electrons from the alkali metal to the triple bond, with abstraction of protons from the ammonia solvent.Draw curved arrows to show the movement of electrons in this step of the mechanism.Arrow-pushing Instructions

Chemistry
1 answer:
NISA [10]3 years ago
6 0

Answer:

Explanation:

The movement of the electrons is illustrated in the picture attached to this answer. It is a four-step reaction mechanism.

First STEP: The first step involves the transfer of an electron from sodium to form a radical anion.

Second STEP: This radical anion then removes a proton/hydrogen from ammonia in a bid to neutralize itself (hence the hydrogen becomes bonded to the anion).

Third STEP: The sodium (from NaNH₂ formed) transfers an electron again to produce a vinyl carbanion.

Fourth STEP: The carbanion then removes a proton/hydrogen from ammonia (like in the second step) to form a neutral trans-alkene.

NOTE: The circled numbers denote each step while the mechanism on the left represents the use of any alkyl group (R and R') while the mechanism on the right assumes both alkyl groups are methyl. Hence, 2-butyne started the reaction and the final product was trans-2-butene.

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Vladimir79 [104]
C. 14 protons and 14 electrons
6 0
3 years ago
Consider the following unbalanced chemical equation. C5H12(l) + O2(g) → CO2(g) + H2O(l) If 21.9 grams of pentane (C5H12) are bur
Marina CMI [18]

Answer : The mass of water produced will be 32.78 grams.

Explanation : Given,

Mass of C_5H_{12} = 21.9 g

Molar mass of C_5H_{12} = 72.15 g/mole

Molar mass of H_2O = 18 g/mole

First we have to calculate the moles of C_5H_{12}.

\text{Moles of }C_5H_{12}=\frac{\text{Mass of }C_5H_{12}}{\text{Molar mass of }C_5H_{12}}=\frac{21.9g}{72.15g/mole}=0.3035moles

Now we have to calculate the moles of H_2O.

The balanced chemical reaction will be,

C_5H_{12}(l)+8O_2(g)\rightarrow 5CO_2(g)+6H_2O(l)

From the balanced reaction we conclude that

As, 1 mole of C_5H_{12} react to give 6 moles of H_2O

So, 0.3035 moles of C_5H_{12} react to give 0.3035\times 6=1.821 moles of H_2O

Now we have to calculate the mass of H_2O.

\text{Mass of }H_2O=\text{Moles of }H_2O\times \text{Molar mass of }H_2O

\text{Mass of }H_2O=(1.821mole)\times (18g/mole)=32.78g

Therefore, the mass of water produced will be 32.78 grams.

3 0
3 years ago
What is the daughter nucleus (nuclide) produced when 64 Cu Cu64 undergoes beta decay by emitting an electron? Replace each quest
kenny6666 [7]

<u>Answer:</u> The daughter nuclide formed by the beta decay of given isotope is _{30}^{64}\textrm{Zn}

<u>Explanation:</u>

Beta decay is defined as the process in which beta particle is emitted. In this process, a neutron gets converted to a proton and an electron.

The released beta particle is also known as electron.

_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0\beta

We are given:

Parent isotope = _{29}^{64}\textrm{Cu}

The chemical equation for the beta decay process of _{29}^{64}\textrm{Cu} follows:

_{29}^{64}\textrm{Cu}\rightarrow _{30}^{64}\textrm{Zn}+_{-1}^0\beta

Hence, the daughter nuclide formed by the beta decay of given isotope is _{30}^{64}\textrm{Zn}

4 0
3 years ago
Hellllpppppppp helppppppppp
mixas84 [53]

Answer :

Charles's Law : It is defined as the volume is directly proportional to the temperature of the gas at constant pressure and number of moles.

Mathematically,

V\propto T

                                Boiling water bath        Cool bath 1       Cool bath 2

Temperature (⁰C)                  99                              17                       2

Temperature (K)(T)    273+99=372             273+17=290      273+2=275

Volume of water                  0.0                             27.0                34.0

in cool flask (mL)

Volume of water=              135.8                           135.8               135.8

Air in flask (mL)

Volume of air                    135.8                           108.8               101.8

in cool flask (V)

\frac{V}{T}                                \frac{135.8}{372}=0.365             \frac{108.8}{290}=0.375         \frac{101.8}{275}=0.370

The graph volume versus temperature for a gas is shown below.

3 0
3 years ago
Which of the following is NOT a property of bases? Which of the following is NOT a property of bases? Bases dissolve many metals
Hitman42 [59]

Bases dissolve many metals.

8 0
3 years ago
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