Charles law gives the relationship between volume and temperature of gas.
It states that at constant pressure volume is directly proportional to temperature
Therefore
V/ T = k
Where V - volume T - temperature in kelvin and k - constant
V1/T1 = V2/T2
Parameters for the first instance are on the left side and parameters for the second instance are on the right side of the equation
Substituting the values in the equation
267 L/ 480 K = V / 750 K
V = 417 L
Final volume is 417 L
The compound's molecular formula is C2H6. This is obtained by:
mass moles divided by smallest moles
C 32g 32/12 = 2.67 1
H 8g 8/1.01 = 7.92 approx. 3
Next, divide both terms by the smallest number of moles, 2.67. This gives 1 and 3. So the empirical formula is CH3 which has a molar mass of 15g/mol. Given the molar mass of the molecular formula as 30g/mole, we can calculate the factor by which to multiply the subscripts of CH3.
X = molar mass of molecular formula / molar mass of empirical formula = 30/15
X=2
So (CH3)2 is C2H6.
The rate constant of a reaction : 8.3 x 10⁻⁴
<h3>Further explanation</h3>
Given
rate = 1 x 10⁻² (mol/L)/s, [A] is 2 M, [B] is 3 M, m = 2, and n = 1
Required
the rate constant
Solution
For aA + bB ⇒ C + D
Reaction rate can be formulated:
![\large{\boxed{\boxed{\bold{r~=~k.[A]^a[B]^b}}}](https://tex.z-dn.net/?f=%5Clarge%7B%5Cboxed%7B%5Cboxed%7B%5Cbold%7Br~%3D~k.%5BA%5D%5Ea%5BB%5D%5Eb%7D%7D%7D)
the rate constant : k =
![\tt k=\dfrac{rate}{[A]^m[B]^n}\\\\k=\dfrac{1.10^{-2}}{2^2\times 3^1}\\\\k=8.3\times 10^{-4}](https://tex.z-dn.net/?f=%5Ctt%20k%3D%5Cdfrac%7Brate%7D%7B%5BA%5D%5Em%5BB%5D%5En%7D%5C%5C%5C%5Ck%3D%5Cdfrac%7B1.10%5E%7B-2%7D%7D%7B2%5E2%5Ctimes%203%5E1%7D%5C%5C%5C%5Ck%3D8.3%5Ctimes%2010%5E%7B-4%7D)
Answer:
(B) The Jalican government did not intend the new fuel-efiiciency requirement to be a pollution-reduction measure.
Explanation:
What it was expressed is about to reduce dependence on imported oil.