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andriy [413]
3 years ago
11

a toy train is moved towards a magnet that cannot move. what happens to the potential energy in the system of magnets during the

movement​
Physics
1 answer:
professor190 [17]3 years ago
6 0

Answer:

Dakota moves a magnetic toy train toward a magnet that cannot move. What happens to the potential energy in the system of magnets during the movement? The potential energy increases because the train moves against the magnetic force. The potential energy decreases because the train moves against the magnetic force.

I hope this helps you :)

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If a net force of 800n is acting on an object with a mass of 60kg. What would be the objects accelerations
aivan3 [116]

Answer: 13.33 m/s^2

Explanation:

Force is the product of mass of an object and its acceleration.

i.e Force = Mass x Acceleration

Since Force on object = 800N

Mass of object = 6Kg

Acceleration = ?

Then, Force = Mass x Acceleration

800N = 60Kg x Acceleration

Acceleration = (800N/60kg)

Acceleration = 13.33 m/s^2 (The unit of acceleration is metre per second square)

Thus, the objects accelerations is 13.33 m/s^2

5 0
4 years ago
Select the best answer.<br> When was traditional chemistry started?
sergejj [24]
17th Century
In 1661 he founded a scientific society which later became known as the Royal Society of England. Traditional Chemistry - The Mid 17th Century to mid 19th Century By this time scientists were using the "modern method" of discovery by testing theories with experiments.
8 0
3 years ago
An asteroid, whose mass is 3.6 × 10-4 times the mass of Earth, revolves in a circular orbit around the Sun at a distance that is
frosja888 [35]

Answer:

a) 2.02 years

b) 8.1 x 10⁻⁸.

Explanation:

Time period of a rotating body T² is proportional to radius of orbit R³ So

T₁² / T₂² = R₁³ /R₂³ ( T₁ and R₁ is time period and radius of orbit of the earth .)

1² / T₂² =( 1/1.6)³

T₂ = 2.02 years.

Kinetic energy of an orbiting body = 1/2 m v₀² ( v₀ is orbital speed)

= 1/2 m x 2 g R = m x G m/R² X R= m² x G /R

Kinetic energy of asteroid K₁ / kinetic energy of earth K₂ =

(mass of asteroid/mass of earth)² x( radius of earth / radius of asteroid)

=( 3.6 x 10⁻⁴)² x 1/1.6 = 8.1 x 10⁻⁸ .

7 0
3 years ago
The parking brake on a 1000 kg Cadillac has failed, and it is rolling slowly, at 1 mph , toward a group of small children. Seein
GalinKa [24]
Um of momenta = 0( Since both the cars stop) 
<span>Let m1 be the mass of the cadillac and m2 be the mass of the volkswagen. </span>
<span>then, v1=speed of cadillac and v2=speed of volkswagen. </span>
<span>Therefore, (m1)*(v1) + (m2)*(v2) = 0 </span>
<span>Substituting, </span>
<span>(1000*4) + (2000*v2) = 0 </span>
<span>4000 = - 2000 v2 </span>
<span>Therefore, v2= - 2 m/s. </span>
6 0
3 years ago
A slingshot can project a pebble at a speed as high as 38.0 m/s. (a) If air resistance can be ignored, how high (in m) would a p
kipiarov [429]

Answer:

73.67 m

Explanation:

If projected straight up, we can work in 1 dimension, and we can use the following kinematic equations:

y(t) = y_0 + V_0 * t + \frac{1}{2} a t^2

V(t) = V_0 + a * t,

Where y_0 its our initial height, V_0  our initial speed, a the acceleration and t the time that has passed.

For our problem, the initial height its 0 meters, our initial speed its 38.0 m/s, the acceleration its the gravitational one ( g = 9.8 m/s^2), and the time its uknown.

We can plug this values in our equations, to obtain:

y(t) =  38 \frac{m}{s} * t - \frac{1}{2} g t^2

V(t) = 38 \frac{m}{s} - g * t

note that the acceleration point downwards, hence the minus sign.

Now, in the highest point, velocity must be zero, so, we can grab our second equation, and write:

0 m = 38 \frac{m}{s} - g * t

and obtain:

t = 38 \frac{m}{s} / g

t = 38 \frac{m}{s} / 9.8 \frac{m}{s^2}

t = 3.9 s

Plugin this time on our first equation we find:

y = 38 \frac{m}{s} * 3.9 s - \frac{1}{2} 9.8 \frac{m}{s^2} (3.9 s)^2

y=73.67 m

6 0
4 years ago
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