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2 years ago

1. A point scored when the ball passes between the goal posts is considered a

Physics

1 answer:

Maru [420]2 years ago

4 0

Answer:

Goal or Field Goal

Explanation:

It is a goal in a sport like hockey or it is a field goal in football.

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A car accelerates at a constant rate from 0 to 50 mph in three fourths min. How far does the car travel during that time?

Helen [10]

Answer:

the car have travelled 0.31 mile during that time

Explanation:

Applying the Equation of motion;

s = 0.5(u+v)t

Where;

s = distance travelled

u = initial speed = 0 mph

v = Final speed = 50 mph

t = time taken = 3/4 min = 3/4 ÷ 60 hours = 1/80 hour

Substituting the given values into the equation;

s = 0.5(0+50)×(1/80)

s = 0.3125 miles

s ~= 0.31 mile

the car have travelled 0.31 mile during that time

8 0

2 years ago

If the frequency of the motion of a simple harmonic oscillator is doubled, by what factor does the maximum speed of the oscillat

Maksim231197 [3]

Answer:

If the frequency of the motion of a simple harmonic oscillator is doubled , then maximum speed of the oscillator changes by the factor 2

Explanation:

We know that in a simple harmonic oscillator the maximum speed is given by

$v_{max}$ = $Aw$

Here A is amplitude which is constant , so from above equation we see that maximum speed is directly proportional to $w\\$ of the oscillation .

Since $w = 2 \pi f$

$v_{max}^{|}/v_{max} = 2f/f$ = 2

Where $v_{max}^{|}$ is the maximum speed when frequency is doubled .

6 0

2 years ago

An object of irregular shape has a characteristic length of L = 0.5 m and is maintained at a uniform surface temperature of Ts =

goblinko [34]

Answer:

The value of the average convection coefficient is 20 W/Km².

Explanation:

Given that,

For first object,

Characteristic length = 0.5 m

Surface temperature = 400 K

Atmospheric temperature = 300 K

Velocity = 25 m/s

Air velocity = 5 m/s

Characteristic length of second object = 2.5 m

We have same shape and density of both objects so the reynold number will be same,

We need to calculate the value of the average convection coefficient

Using formula of reynold number for both objects

$R_{1}=R_{2}$

$\dfrac{u_{1}L_{1}}{\eta_{1}}=\dfrac{u_{2}L_{2}}{\eta_{2}}$

$\dfrac{h_{1}L_{1}}{k_{1}}=\dfrac{h_{2}L_{2}}{k_{2}}$

Here, $k_{1}=k_{2}$

$h_{2}=h_{1}\times\dfrac{L_{1}}{L_{2}}$

$h_{2}=\dfrac{q}{T_{2}-T_{1}}\times\dfrac{L_{1}}{L_{2}}$

Put the value into the formula

$h_{2}=\dfrac{10000}{400-300}\times\dfrac{0.5}{2.5}$

$h_{2}=20\ W/Km^2$

Hence, The value of the average convection coefficient is 20 W/Km².

7 0

3 years ago

A second order measuring system has a known natural frequency of 2000 Hz and damping ratio of 0.8. Would it be satisfactory to u

Anna007 [38]

Answer:

The expected dynamic error is 0.019

The phase shift is -23.10°C

Explanation:

The explanation is shown on the first uploaded image

7 0

2 years ago

What is found in both plant and animal cells but is much larger in plant cells

djverab [1.8K]

The vacuoles because the plant's central vacuole is bigger.

3 0

2 years ago

Read 2 more answers