Answer:
T₂ = 305.17 K
Explanation:
Given that,
Heat, Q = 6000 J
Mass, m = 200 gram
Initial temperature, T₁ = 25° C
We need to find its final temperature. Let it is T₂.
We know that,

Where
c is the specific heat of water, c = 4.18 J/g°C
So,

So, the final temperature is equal to 305.17 K.
Answer:
θr = 55.2 °
Explanation:
The law of reflection states that the angle of incidence and the angles of reflection is the same.
Let's use trigonometry to find the angle between the reflected ray, where the horizontal distance x = 55.9 cm and the vertical distance is y = 38.9 cm
tan θ = y / x
tan θ = 38.9 / 55.9
θ = tan⁻¹ (0.6959)
θ = 34.8°
This angle is measured with respect to the x-axis (horizontal), but in general the angles in optics are measured from the y-axis so that the angle is
θ = 90 - 34.8
θr = 55.2 °
Answer:
A)0.00022s b)40363.6N c) 0.025m/s
Explanation:
Mass = 24g = 0.024kg, distance though the target = thickness of the target = 25cm = 0.25m
Initial speed of the bullet = 1300m/s, final speed = 930m/s
Using equation of motion
Distance = 1/2(vf+vi)*t (time in seconds)
t = 0.25*2/(1300+930) = 0.00022s
B) force exerted on the body
F = ma = m* (vf-vi)/t = 0.024*(930-1300)/0.00022
F = -40363N, it is negative because the body decelerated during this motion
C) using law of conservation of momentum,
M1*U1+ M2*U2(M2and U1 are the mass and initial speed of the body) = M1V1+ M2V2
The target was at rest so initial speed U2 = 0
0.024*1300 + 360*0 = 0.024*930 + 360*V2
31.2 = 22.32+360*V2
31.2-22.33 = 360*V2
V2 = 8.88/360 = 0.025m/s
The projectile maintains its horizontal component of speed because there's nothing exerting any horizontal force on it. <em>(b) </em>
Gravity has no effect on horizontal motion.
Answer:
F = 5.33*10^-4N
Explanation:
to find the electrostatic force you use the Coulomb's law, given by the formula:

k: Coulomb's constant = 8.89*10^9 Nm^2/C^2
q_a: charge of A = 2.0*10^{-6}C
q_B: charge of B = -3.0*10^{-6}C
r: distance between the spheres = 10.0m
By replacing all these values you obtain:

hence, the forcebetween the spheres is about 5.33*10^-4N