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rusak2 [61]
3 years ago
9

A biker pedals hard for 3 seconds. What is his initial velocity if he accelerated by 4m/s2 until he's going 20m/s. (Which equati

on should I use?)

Physics
1 answer:
____ [38]3 years ago
4 0

Answer:

answer is option 4

Explanation:

you have to use option 4 because u need to find out initial velocity (Vi)

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How does mass influence the kinetic energy and the potential energy of an object?
vladimir2022 [97]

Answer:

The faster an object moves, the more kinetic energy it has. The more mass an object has, the more kinetic energy it has.

Explanation:

8 0
3 years ago
Read 2 more answers
An elevator is accelerating upward at a rate of 3.6 m/s2. a block of mass 24 kg hangs by a low-mass rope from the ceiling, and a
kozerog [31]
The answer:

<span>When the elevator accelerates upward at a rate of 3.6 m/s², the value of the acceleration becomes

</span>A=g+3.6=13.4 m/s²
and by using the newton's law, F=mass x A, we have 
T1= (24 + 90 )x 13.4= 1527.6 N, where T1 is the <span>Tension in upper rope
</span> and 
T2= ( 90 )x 13.4= 1206N, where T2 is the Tension in lower rope

When the elevator accelerates downward at a rate of 3.6 m/s², the value of the acceleration becomes
A=9.8 - 3.6 = 6.2 m/s²

T1= (24 + 90 )x 6.2= 706.8 N, where T1 is the Tension in upper rope
 and 
T2= ( 90 )x 6.2= 558N, where T2 is the Tension in lower rope


5 0
3 years ago
What is that distance traveled by an arrow going 78 m/s for 5 seconds
pshichka [43]

Explanation:

velocity=distance/time

distance= velocity×time

distance= 78×5=390m

8 0
3 years ago
A car is brought to rest uniformly in 6 seconds. The initial velocity of the car was 24 m/s. How far does the car travel while d
pav-90 [236]

Answer:

v=u+at

24=0+at

24=a×6

a=4m/s

hence

s=ut+at^2÷2

s=36m

Explanation:

since the car is brought to rest the u=0

4 0
3 years ago
Archer shoots his arrow towards a target at a distance of 90 m and hits bullseye . Calculate the acceleration and time taken by
goldfiish [28.3K]

Answer:

acceleration = 45 m/s²

Time = 20 seconds

Explanation:

We are given;

Distance; s = 90m

Final velocity;v = 90 m/s

Since shot from rest, initial velocity;u = 0 m/s

So, to find the acceleration, we can use Newton's 2nd law of motion which is;

v² = u² + 2as

Where a is acceleration

Plugging in the values;

90² = 0² + 2a(90)

8100 = 180a

a = 8100/180

a = 45 m/s²

Now, for the time, we will use Newton's 1st law of motion which is;

v = u + at

Where t is time;

So;

90 = 0 + 4.5t

90 = 4.5t

t = 90/4.5

t = 20 seconds

3 0
3 years ago
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