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mart [117]
4 years ago
15

If the rate of change of the magnetic field applied to a loop of wire is doubled, what happens to the induced emf in that loop a

ssuming that all other parameters remain unchanged?
Physics
1 answer:
slava [35]4 years ago
3 0

Answer:

It is doubled.

Explanation:

The EMF( Electromotive force) is usually gotten from an energy source. In this case it is from the magnetic field. However when the other parameters are constant then the main focus is between the EMF and the magnetic field. They have a direct proportion relationship which is why when the magnetic field is doubled the EMF is doubled too.

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photon strikes the surface of tungsten and an electron is emitted. what is the maximum possible speed of the electron?
zalisa [80]

Answer: The maximum possible speed v is √2(  hν - Ф  ) / m

Explanation: You could be referring to the provided explanation, despite the fact that the question isn't comprehensive. When a photon collides with the surface of any metal, it transmits all of its energy to the electron in the atom. The collision causes the electron to travel with a certain amount of kinetic energy. This is referred to as the photoelectric effect. The maximum kinetic energy is calculated using Einstein's equation for the photoelectric effect:

K.E. = hν - Ф

½ mv² = hν - Ф

Hence the maximum possible speed is:

v = √2(  hν - Ф  ) / m

For more information on the photoelectric effect refer to this link: brainly.com/question/25027428

#SPJ4

3 0
2 years ago
Important!
andreyandreev [35.5K]

Answer:

b

Explanation:

8 0
3 years ago
Consider a particle moving along the x-axis where x(t) is the position of the particle at time t, x' (t) is its velocity, and x'
nignag [31]

The position of the particle is given by:

x(t) = t³ - 12t² + 21t - 9

Differentiate x(t) with respect to t to find the velocity x'(t):

x'(t) = 3t² - 24t + 21

Differentiate x'(t) with respect to t to find the acceleration x''(t):

x''(t) = 6t - 24

5 0
3 years ago
After hitting the spring, the block is bounced back up the ramp. The maximum compression of the spring is Δx=0.03m, and the spri
Lyrx [107]

Answer:

v = 1.28 m/s

Explanation:

Given that,

Maximum compression of the spring, \Delta x=0.03\ m

Spring constant, k = 800 N/m

Mass of the block, m = 0.2 kg

To find,

The velocity of the block when it first reaches a height of 0.1 m above the ground on the ramp.

Solution,

When the block is bounced back up the ramp, the total energy of the system remains conserved. Let v is the velocity of the block such that,

Initial energy = Final energy

\dfrac{1}{2}kx^2=mgh+\dfrac{1}{2}mv^2

Substituting all the values in above equation,

\dfrac{1}{2}\times 800\times 0.03^2=0.2\times 9.8\times 0.1+\dfrac{1}{2}\times 0.2\times v^2

v = 1.28 m/s

Therefore the velocity of block when it first reaches a height of 0.1 m above the ground on the ramp is 1.28 m/s.

5 0
3 years ago
Which of the following is the proper unit for measuring power? Newton Joules Watts Meters
fredd [130]
The unit for power is Watts. the newton is a unit for force. joules for energy and meters for distance
3 0
3 years ago
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