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jeyben [28]
3 years ago
11

What happens to jetstream’s as they get closer to the equator

Physics
2 answers:
MAVERICK [17]3 years ago
6 0

Answer:They stop because jet streams follow boundaries between hot and cold air.

Explanation:

Semmy [17]3 years ago
6 0

Answer:

Hey!

Jet Streams don't really tend to move towards the Equator...

But when the area they are located becomes warm, the tend to STOP SHIFTING and deliver a constant temperature of air (most commonly it is warm air)

They follow boundaries formed when air MOVES AWAY FROM THE EQUATOR and the EARTHS ROTATION!

Explanation:

HOPE THIS HELPS!!

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Most towns use a water tower to store water and provide pressure in the pipes that deliver water to customers. The figure below
MatroZZZ [7]

The effective height of the water for Smith's house will be 24.61m.

<h3>How to calculate the height?</h3>

Based on the information given, the volume of the water in sphere will be:

= 4/3πr³ = (5.80 × 10^5)/1000

= 4.18r³ = 580

r³ = 138.7

r = 5.18m

The effective height of the water will be:

= 18.0 + 2(5.18)

= 28.36

The gauge pressure at Faucet of Jones house will be:

= pgh

= 1000(9.8)(28.36)

= 277.9kPa

The effective height of the water for Smith's house will be:

= 18.0 + 2(5.18) - 3.75

= 24.61m

The gauge pressure at Faucet of Jones house will be:

= 1000 × 9.8 × 24.61

= 241.2kPa

Learn more about height on:

brainly.com/question/983412

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8 0
1 year ago
Which of the following is group 1? a. alkali metals b. alkaline earth metals c. halogens d. transition metals
Elanso [62]
The answer is A. Alkali metals
4 0
3 years ago
Read 2 more answers
balls a, with a mass of 20 kg, is moving to the right at 20 m/s. At what velocity should Ball B, with a mass of 40 kg, move so t
Leya [2.2K]
In that case, their momentum must be equal. 
So, m1v1 = m2v2
20 * 20 = 40 * v2
v2 = 400 / 40
v2 = 10

In short, Your Answer would be: 10 m/s

Hope this helps!
3 0
3 years ago
you are piloting a small plane and you want to reach an airport 450 km due south in 3.0 h a wind is blowing from the west 50.0 k
alex41 [277]

Answer:

You should choose airspeed 158.11 km/h at 18.4° west of south

Explanation:

The distance to the air port is 450 km due to south

You should to reach the airport in 3 hours

→ Velocity = distance ÷ time

→ Distance = 450 km , time = 3 hours

→ The velocity of your plane = 450 ÷ 3 = 150 km/h due to south

A wind is blowing from west 50 km/h

We need to know what heading and airspeed you should choose to

reach your destination

At first we must find the resultant velocity of your plane and the wind

The south and west are perpendicular, then the resultant velocity is

→ v_{R}=\sqrt{(v_{p})^{2}+(v_{w})^{2}}

→ v_{p}=150 km/h ,  v_{w}=50 km/h

→ v_{R}=\sqrt{(150)^{2}+(50)^{2}}=158.11 km/h

To cancel the velocity of the wind, the pilot should maintain the velocity

of the plane at 158.11 km/h

The direction of the velocity is the angle between the resultant velocity

and the vertical (south)

→ The direction of the velocity is tan^{-1}\frac{50}{150}=18.4°

The direction of the velocity is 18.4° west of south

<em>You should choose airspeed 158.11 km/h at 18.4° west of south</em>

8 0
3 years ago
Why do you need to learn about Volcanoes?
nevsk [136]
That they sometimes explode?
5 0
3 years ago
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