Our goal is to find the area
area=1/2 times base times height
we know the height is 7.9 but what is the base?
use the pythagorean theorem twice
alrighty
so
remember for legs length a and b and hytponuse c in a right triangle
a²+b²=c²
we need AD and DC
so
AD²+7.9²=9.4²
AD=√25.95
DC²+7.9²=23.2²
DC=√475.83
so
AD+DC=base=(√25.95)+(√475.83)
area=1/2bh
area=1/2((√25.95)+(√475.83))(7.9)
area≈106.28518654591426812803776879893
round to 2 decimal places
area≈106.29 square units
Hello there! An example problem for this could be:
Emile is looking for a cell-phone plan. His two options are one that costs $40 up front, and costs $0.01 per text, represented by x. The second one is 15 dollars up front and costs $0.06 for each text message. Emile figures that for the first package he has to send 500 texts or more to make it less than the second one.
<span>You can select from any of the 8 on the first day, leaving 7 to choose from on the second day, leaving 6 for the third. So, 8 x 7 x 6 x 5 x 4 x 3 x 2 or 8! That's 8factorial, so multiply those out or use a calculator to get 8! and that is your answer.</span>
16. 5x^3 y^-5 • 4xy^3
20x^4y^-2
20x^4 • 1/y^2
=20x^4/y^2
17. -2b^3c • 4b^2c^2
= -8b^5c^3
18. a^3n^7 / an^4 (a^3 minus a = a^2 same as n^7 minus n^4 = n^3)
=a^2n^3
19. -yz^5 / y^2z^3
= -z^2/y
20. -7x^5y^5z^4 / 21x^7y^5z^2 (divide -7 to 21 and minus xyz)
= -z / 3x^2
21. 9a^7b^5x^5 / 18a^5b^9c^3
=a^2c^2 / 2b^4
22. (n^5)^4
n ^5 x 4
=n^20
23. (z^3)^6
z ^3 x 6
=z^18
