Question

An electron in an x-ray machine is accelerated through a potential difference of 1.00× 10⁴V before it hits the target. What is the kinetic energy of the electron in electron volts?(a) 1.00 × 10⁴ eV(b) 1.60 × 10⁻¹⁵ eV(c) 1.60 × 10⁻²² eV(d) 6.25× 10²² eV(e) 1.60 × 10⁻¹⁹ eV

Answer 1

The kinetic energy of an electron in an x-ray machine which is accelerated through a potential difference of 1.00× 10⁴V is 1.00×$10^4$eV (Option a)

How is the kinetic energy of an electron is calculated in electron volts?

• The kinetic energy of  an electron is estimated to be 4.55 ×$10^-^2^5$ J
• Change in kinetic energy , i.e ΔK = The negative of the change in potential energy, i.e -qV
• ΔK = -qV
• ΔK = -(e)V
• ΔK = -(1.00× 10⁴V)
• Therefore ΔK = 1.00×$10^4$eV

What is electron volt?

• Kinetic energy is the electron volt where E = qV

• E = ΔK = -qV

• ( E is the energy of any charge, q is the charge and V is the voltage )

• Electron volt is the amount of energy, an electron does to accelerate through any potential difference of 1V

To learn more about kinetic energy of electron, refer

brainly.com/question/21208918

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