Answer:
solved
Explanation:
a) F_net = (F2 - F3)i - F1 j
b) |Fnet| = sqrt( (F2 - F3)^2 + F1^2)
= sqrt( (9- 5)^2 + 1^2)
= 4.123 N
c) θ = tan^-1( (Fnet_y/Fnet_x)
= tan^-1( -1/(9-5) )
= -14.036°
Answer:
201 J
Explanation:
Work done by the pilot is defined by the equation
F d cos θ = 25 × 10 × cos 36.5 = 200.96 approx 201 J
Answer:
Hi
The acceleration in m/s 2 is:
a= (v-u)/t
a= (29.0-0)/5.75
a= 5.043478261
a= 5.04 (3s.f)