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Vaselesa [24]
3 years ago
5

16 points

Physics
1 answer:
Fynjy0 [20]3 years ago
3 0

Answer:

am pretty sure u have to measure like my name is Justin am cracked at fortnite my Guy

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Do I divided or multiply
Papessa [141]

Weight is mass x gravity, so you'd multiply the mass of the astronaut by the gravitational pull.

6 0
4 years ago
Read 2 more answers
What fundamental frequency would you expect from blowing across the top of an empty soda bottle that is 24 cm deep
kari74 [83]

Answer:

708.3 Hz

Explanation:

For an open-air column, like the empty can, the fundamental frequency is given by

f_1 = \frac{v}{2L}

where

v = 340 m/s is the speed of sound

L is the length of the column

In this problem, the length of the bottle is

L = 24 cm = 0.24 m

Therefore, the fundamental frequency is

f_1 = \frac{340 m/s}{2(0.24 m)}=708.3 Hz

8 0
3 years ago
The wavelength of the wave in the diagram below is given by letter ____ and the amplitude of the wave in the diagram below given
RideAnS [48]
The wavelength of the wave is given by the letter A. And the amplitude of the wave is given by the letter B.
4 0
3 years ago
Draw a circuit that uses the resistors listed below as well as a 12V battery source. For your circuit, determine (a) the total r
Zepler [3.9K]

Answer: hello your questions lacks the required resistor values therefore i will provide a general answer using an example

answer : a) 14 ohms  b) 0.86 amps   c) 10.32 V

Explanation:

Assuming the resistors are : 3 ohms , 4 ohms and 5 ohms

Voltage source = 12V

<u>Assuming that the Resistors are in series </u>

<u>a) Determine Total resistance </u>

Req = R1 + R2 + R3

       = 3 + 4 + 5 = 14 ohms

<u>b) Total current </u>

Ieq = V / Req

      = 12 / 14 =  0.86 amps

<u>c) The Total Voltage over the entire system </u>

Vt = ∑ Voltage drops

    = ( 0.86 * 3 ) + ( 0.86 * 4 ) + ( 0.86 * 5 )

    = 10.32 V

5 0
3 years ago
What is the final temperature when a 3.0 kg gold bar at 99 0C is dropped into 0.22 kg of water at 25oC?
liq [111]

Answer:

46.9 C

Explanation:

The heat released by the gold bar is equal to the heat absorbed by the water:

m_g C_g (T_g-T_f)=m_w C_w (T_f-T_w)

where:

m_g = 3.0 kg is the mass of the gold bar

C_g=129 J/kg C is the specific heat of gold

T_g=99 C is the initial temperature of the gold bar

m_w = 0.22 kg is the mass of the water

C_w=4186 J/kg C is the specific heat of water

T_w=25 C is the initial temperature of the water

T_f is the final temperature of both gold and water at equilibrium

We can re-arrange the formula and solve for T_f, so we find:

m_g C_g T_g -m_g C_g T_f = m_w C_w T_f - m_w C_w T_w\\m_g C_g T_g +m_w C_w T_w= m_w C_w T_f +m_g C_g T_f \\T_f=\frac{m_g C_g T_g +m_w C_w T_w}{m_w C_w + m_g C_g}=\\=\frac{(3.0)(129)(99)+(0.22)(4186)(25)}{(0.22)(4186)+(3.0)(129)}=\frac{38313+23023}{921+387}=\frac{61336}{1308}=46.9 C

5 0
3 years ago
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