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3 years ago

16 points

Physics

1 answer:

Fynjy0 [20]3 years ago

3 0

Answer:

am pretty sure u have to measure like my name is Justin am cracked at fortnite my Guy

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Do I divided or multiply

Papessa [141]

Weight is mass x gravity, so you'd multiply the mass of the astronaut by the gravitational pull.

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4 years ago

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What fundamental frequency would you expect from blowing across the top of an empty soda bottle that is 24 cm deep

kari74 [83]

Answer:

708.3 Hz

Explanation:

For an open-air column, like the empty can, the fundamental frequency is given by

$f_1 = \frac{v}{2L}$

where

v = 340 m/s is the speed of sound

L is the length of the column

In this problem, the length of the bottle is

L = 24 cm = 0.24 m

Therefore, the fundamental frequency is

$f_1 = \frac{340 m/s}{2(0.24 m)}=708.3 Hz$

8 0

3 years ago

The wavelength of the wave in the diagram below is given by letter ____ and the amplitude of the wave in the diagram below given

RideAnS [48]

The wavelength of the wave is given by the letter A. And the amplitude of the wave is given by the letter B.

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3 years ago

Draw a circuit that uses the resistors listed below as well as a 12V battery source. For your circuit, determine (a) the total r

Zepler [3.9K]

Answer: hello your questions lacks the required resistor values therefore i will provide a general answer using an example

answer : a) 14 ohms b) 0.86 amps c) 10.32 V

Explanation:

Assuming the resistors are : 3 ohms , 4 ohms and 5 ohms

Voltage source = 12V

Assuming that the Resistors are in series 

a) Determine Total resistance

Req = R1 + R2 + R3

= 3 + 4 + 5 = 14 ohms

b) Total current

Ieq = V / Req

= 12 / 14 = 0.86 amps

c) The Total Voltage over the entire system

Vt = ∑ Voltage drops

= ( 0.86 * 3 ) + ( 0.86 * 4 ) + ( 0.86 * 5 )

= 10.32 V

5 0

3 years ago

What is the final temperature when a 3.0 kg gold bar at 99 0C is dropped into 0.22 kg of water at 25oC?

liq [111]

Answer:

46.9 C

Explanation:

The heat released by the gold bar is equal to the heat absorbed by the water:

$m_g C_g (T_g-T_f)=m_w C_w (T_f-T_w)$

where:

$m_g = 3.0 kg$ is the mass of the gold bar

$C_g=129 J/kg C$ is the specific heat of gold

$T_g=99 C$ is the initial temperature of the gold bar

$m_w = 0.22 kg$ is the mass of the water

$C_w=4186 J/kg C$ is the specific heat of water

$T_w=25 C$ is the initial temperature of the water

$T_f$ is the final temperature of both gold and water at equilibrium

We can re-arrange the formula and solve for T_f, so we find:

$m_g C_g T_g -m_g C_g T_f = m_w C_w T_f - m_w C_w T_w\\m_g C_g T_g +m_w C_w T_w= m_w C_w T_f +m_g C_g T_f \\T_f=\frac{m_g C_g T_g +m_w C_w T_w}{m_w C_w + m_g C_g}=\\=\frac{(3.0)(129)(99)+(0.22)(4186)(25)}{(0.22)(4186)+(3.0)(129)}=\frac{38313+23023}{921+387}=\frac{61336}{1308}=46.9 C$

5 0

3 years ago