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kotegsom [21]
3 years ago
9

50 POINTS please show the step by step process.I already know the answers i just the steps!!

Mathematics
2 answers:
djyliett [7]3 years ago
7 0

Answer: 8x

2.9543127e+21xy

9x

Step-by-step explanation:

4x^2=16x     28x=28x     36=36      16x+28x-36   16+28=44-36=8x

125x^6= 30517578125x    27y^15= 2.9543127e+21                             30517578125x-2.9543127e+21= 2.9543127e+21xy

4-7=3+x=3x    5-8=3+x=3x   3x * 3x= 9x

Svetach [21]3 years ago
4 0

Answer:

<h2>1.   4(x² + 7x - 9)</h2><h2>2.  (5x² - 3y⁵) (25x⁴ + 15x²y⁵ + 9y¹⁰)</h2><h2>3.  20x² - 67x + 56</h2>

Step-by-step explanation:

1.  factor 4x^2+28x-36

= 4x² + 28x - 36

re-write 36=4*9,  and 28=4*7

= 4x² + 4 * 7x - 4 * 9

factor out common term:

<h3>= 4(x² + 7x - 9)</h3>

2.  factor 125x^6-27y^15

= 125x⁶ - 27y¹⁵

=(5x²)³ - (3y⁵)₃

apply difference of cubes: x³-y³ = (x-y)(x²+xy+y²)

= (5x² - 36y⁵)(5²x⁴ + 5 * 3x²y⁵ + 3²y¹⁰)

refine:

<h3>= (5x² - 3y⁵) (25x⁴ + 15x²y⁵ + 9y¹⁰)</h3>

3. multiply (4x-7)(5x-8)

apply the FOIL method

= 4x * 5x + 4x (-8) + (-7) * 5x + (-7) (-8)

<h3>= 20x² - 67x + 56</h3>
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How do I do 8b(ii) ? Please help me thank you!
Mila [183]
Step One
======
Find the length of FO (see below)

All of the triangles are equilateral triangles. Label the center as O
FO = FE = sqrt(5) + sqrt(2)

Step Two
======
Drop a perpendicular bisector from O to the midpoint of FE. Label the midpoint as J. Find OJ

Sure the Pythagorean Theorem. Remember that OJ is a perpendicular bisector.

FO^2 = FJ^2 + OJ^2
FO = sqrt(5) + sqrt(2)
FJ = 1/2 [(sqrt(5) + sqrt(2)]                                           \
OJ = ??

[Sqrt(5) + sqrt(2)]^2 = [1/2(sqrt(5) + sqrt(2) ] ^2 + OJ^2
5 + 2 + 2*sqrt(10) = [1/4 (5 + 2 + 2*sqrt(10) + OJ^2
7 + 2sqrt(10) = 1/4 (7 + 2sqrt(10)) + OJ^2      Multiply through by 4
28 + 8* sqrt(10) = 7 + 2sqrt(10) + 4 OJ^2    Subtract 7 + 2sqrt From both sides
21 + 6 sqrt(10) = 4OJ^2   Divide both sides by 4
21/4 + 6/4* sqrt(10) = OJ^2
21/4 + 3/2 * sqrt(10) = OJ^2 Take the square root of both sides.
sqrt OJ^2 = sqrt(21/4 + 3/2 sqrt(10) )
OJ = sqrt(21/4 + 3/2 sqrt(10) )

Step three
find h
h = 2 * OJ
h = 2* sqrt(21/4 + 3/2 sqrt(10) ) <<<<<< answer.


7 0
3 years ago
I need help with this geometry question
MArishka [77]

Answer:

Approximately 7.8 units

Step-by-step explanation:

To find the distance between any two points, we can use the distance formula:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

From the graph, we can see that A is (0,0). Let's let this be x₁ and y₁.

B is (-5,6). Let's let this be x₂ and y₂. So, substitute:

d=\sqrt{(-5-0)^2+(6-0)^2}

Simplify:

d=\sqrt{(-5)^2+(6)^2}

Square:

d=\sqrt{25+36}

Add:

d=\sqrt{61}

Take the square root. Use a calculator:

d\approx7.8

So, the distance between them is about 7.8 units.

And we're done!

7 0
3 years ago
Please help out :)) and give a explanation
wolverine [178]

9514 1404 393

Answer:

  y = 3x

Step-by-step explanation:

A proportional relation has the equation ...

  y = kx

To write the desired equation, you need to know the value of k. That can be found from the given information:

  for x = 2, y = 6

  6 = k·2

  3 = k . . . . divide by 2

Now, we know the equation can be written ...

  y = 3x

5 0
3 years ago
Four students took a national standardized test for which the mean was 500 and the standard deviation was 100. If a student’s z-
murzikaleks [220]

z = (x - 500) / 100

1.75 = (x - 500) / 100

175 = x - 500

675 = x

3 0
3 years ago
Read 2 more answers
A line passes through the point (4, -6) and has a slope of 3/2 . Write an equation in slope-intercept form for this line.
tatyana61 [14]

A slope intercept form: y = mx + b where m = slope and b = y -intercept

A slope of 3/2 is given

So y = 3/2 x + b

To find b:

b = y - mx

A line passes through the point (4, -6)

b = -6 - (3/2)(4)

b = -6 - 6

b = - 12

Answer

Equation in  slope intercept form:  y = 3/2 x - 12


8 0
3 years ago
Read 2 more answers
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