The carbon dioxide in the headspace above the liquid is at higher pressure than atmospheric pressure outside the can.
The gas is at a lower volume initially but suddenly has a larger volume available when the can is opened.
The change in pressure as the gas rapidly moves to become dispersed through its new volume causes the "whoosh" sound.
The gas law that applies is Boyle's law.
This above is the exact answer for edgunity
From the data obtained from the tests, the actual boiling point lies between 34°C and 40°C.
The boiling point of a substance is the temperature at which the pressure of the substance becomes equal to atmospheric pressure. Pure substances have a sharp boiling point while impure substances boil over a temperature range.
In this case, the boiling point of the substance after 10 tests is obtained as 37+/−3°C. This implies that the actual boiling point lies between 34°C and 40°C.
Learn more: brainly.com/question/8646601
The number of moles of hydrogen is equal to the number of moles of nitrogen.
According to the ideal gas equation
PV = nRT
where
- P = the pressure of the gas
- V = the volume of gas
- n = the total amount of ideal gas (moles)
- R = the universal gas constant
- T = the temperature
In the problems there are two identical cylinders means, V₁ = V₂
The pressure inside each of two identical cylinders is equal to atmospheric pressure means, P₁ = P₂
Both gases are at the same temperature, means T₁ = T₂
n₁ = n₂
So the total amount of hydrogen gas is equal to total amount of ideal nitrogen gas.
Learn more about the ideal gas equation here: brainly.com/question/27870704
#SPJ4
Answer- 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
Given - Number of moles of Al(NO3)3 - 4 moles
Number of moles of NaCl - 9 moles
Find - Maximum amount of AlCl3 produced during the reaction.
Solution - The complete reaction is - Al(NO3)3 + 3NaCl --> 3NaNO3 + AlCl3
To find the maximum amount of AlCl3 produced during the reaction, we need to find the limiting reagent.
Mole ratio Al(NO3)3 - 4/1 - 4
Mole ratio NaCl - 9/3 - 3
Thus, NaCl is the limiting reagent in the reaction.
Now, 3 moles of NaCl produces 1 mole of AlCl3
9 moles of NaCl will produce - 1/3*9 - 3 moles.
Weight of AlCl3 - 3*133.34 - 400 grams
Thus, 400 grams of AlCl3 is the maximum amount of AlCl3 produced during the experiment.
The equilibria showing how the acetate buffer adjusts to addition of a small amount of NaOH is:
- CH3COOH(aq) + H2O(1) → H30+ (aq) + CH3COO (aq)
<h3>What is a buffer?</h3>
A buffer is a solution which resists changes to its pH when small amounts of strong base or acid is added to it.
Buffers are made from solutions of weak acids and their salts or weak bases and their salts.
The equilibria showing how a buffer made from acetic acid and sodium acetate (NaCH3COO) adjusts to addition of a small amount of NaOH is as follows:
- CH3COOH(aq) + H2O(1) → H30+ (aq) + CH3COO (aq)
Addition of NaOH, a strong base will neutralize the hydronium ion, causing the acetic acid ionization equilibrium to shift to the right to produce more of the acetate ion, the conjugate base.
Learn more about acetate buffer at: brainly.com/question/17490438
