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wolverine [178]
3 years ago
9

The whiye pigment TiO2 is prepared by the reaction of titanium tetrachloride, TiCl4, with water vapor in the gas phase:

Chemistry
1 answer:
omeli [17]3 years ago
5 0

Answer:

\boxed{\text{62.1 kJ}}

Explanation:

The formula for calculating the enthalpy change of a reaction by using the enthalpies of formation of reactants and products is

\Delta_{\text{r}}H^{\circ} = \sum \Delta_{\text{f}} H^{\circ} (\text{products}) - \sum\Delta_{\text{f}}H^{\circ} (\text{reactants})

                          TiCl₄(g) + 2H₂O(g) ⟶ TiO₂(s) + 4HCl(g)

ΔH°f/kJ·mol⁻¹:    -763.2     -241.828     -939.7    -92.307

\begin{array}{rcl}\Delta_{\text{r}}H^{\circ} & = & [-939.7 + 4(-92.307)] - [-763.2 + 2(-241.828)\\& = & [-939.7 - 369.228] - [-763.2 - 483.656]\\& = & -1308.928 + 1246.856\\& = & \mathbf{-62.1}\\\end{array}\\\text{The amount of heat evolved is } \boxed{\textbf{62.1 kJ}}

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Explanation:

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Explanation:


1) The depression of the freezing point of a solvent when you add a solute is a colligative property.


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3) The relation between the number of solute particles and the depresson of the freezing point is proportional: the greater the number of solute particles the greater the freezing point depression.


4) You need to find the solution with the highest freezing point, this is the solution in which the freezing point decreased the least.


5) Then, that is the solution with least number of solute particles.


6) Since all the given solutions have the same molarity (1.0 M), you only have to deal with the possible ionization of the different solutes.


7) NaCl, CaBr₂, AlBr₃, and KCl are ionic compounds, so each unit of them will ionize into two, three, four, and two ions, respectively, while sucrose, being a covalent compound does not dissociate.


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Explanation:

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