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slava [35]
2 years ago
11

Complete and balance the following neutralization reaction Ca(OH)2 + H2SO4

Chemistry
1 answer:
Debora [2.8K]2 years ago
6 0

Answer: Ca(OH)2 (aq) + H2SO4 (aq) ---------->  CaSO4(aq) + 2H2O(l)

Explanation:

Since this is a neutralization reaction, the end product would be salt and water. In this equation Calcium will displace hydrogen from the acid because it is more reactive, resulting in the formation of CaSO4 (salt), while the displaced H2 molecule combines with OH molecules to form water.

The equation of the reaction is thus;

Ca(OH)2 (aq) + H2SO4 (aq) ---------->  CaSO4(aq) + H2O(l), in other to balance it, we add ''2'' to the water molecule in the right hand side of the equation.

Balance equation is  

Ca(OH)2 (aq) + H2SO4 (aq) ---------->  CaSO4(aq) + 2H2O(l)

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Calculate the solubility of carbon dioxide in water at an atmospheric pressure of 0.400 atm (a typical value at high altitude).A
Bond [772]

Answer:

The molar solubility of carbon dioxide gas is 4.662\times 10^{-6} M.

Explanation:

Henry's law states that the amount of gas dissolved or molar solubility of gas is directly proportional to the partial pressure of the liquid.

To calculate the molar solubility, we use the equation given by Henry's law, which is:

C_{CO_2}=K_H\times p_{liquid}

where,

K_H = Henry's constant = 3.50\times 10^{-2}mol/L.atm

p_{CO_2} = partial pressure of carbonated drink

p_{CO_2}=p\times \chi_{CO_2}

where = p = Total pressure = 0.400 atm

\chi_{CO_2} = mole fraction of CO_2=3.33\times 10^{-4}

p_{CO_2}=0.400 atm\times 3.33\times 10^{-4} =0.0001332 atm

Putting values in above equation, we get:

C_{CO_2}=3.5\times 10^{-2}mol/L.atm\times 0.0001332  atm\\\\C_{CO_2}=4.662\times 10^{-6} M

Hence, the molar solubility of carbon dioxide gas is 4.662\times 10^{-6} M.

8 0
2 years ago
If you had excess aluminum, how many moles of aluminum chloride could be produced from 21.0 g of chlorine gas, cl2?
AleksandrR [38]
When aluminum metal is made to contact with chlorine gas (Cl₂), a highly exothermic reaction proceeds. This produces aluminum chloride (AlCl₃) powder. The balanced chemical equation for this reaction is shown below:

2Al(s) + 3Cl₂(g) → 2AlCl₃(s)

Since it was stated that aluminum is in excess, this means that the amount of AlCl₃ produced will only depend on the amount of Cl₂ gas available. The molar mass of Cl₂ is 70.906 g/mol. Using stoichiometry, we have the following equation:

(21.0 g Cl₂/ 70.906 g/mol Cl₂) x 2 mol AlCl₃/ 2 mol Cl₂ = 0.1974 mol AlCl₃

Thus, we have determined that 0.1974 <span>moles of aluminum chloride can be produced from 21.0 g of chlorine gas. </span>
3 0
3 years ago
Calculate the number of moles of solute in 27.55 mL of 0.1185 M K2Cr2O7(aq).
Zinaida [17]

Answer:

0.01185M = moles/0.02755L

0.02755*0.01185=0.00032647

Explanation:

7 0
2 years ago
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7 0
3 years ago
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Answer:

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Explanation:

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