All categories

3 years ago

Complete and balance the following neutralization reaction Ca(OH)2 + H2SO4

Chemistry

1 answer:

Debora [2.8K]3 years ago

6 0

Answer: Ca(OH)2 (aq) + H2SO4 (aq) ----------> CaSO4(aq) + 2H2O(l)

Explanation:

Since this is a neutralization reaction, the end product would be salt and water. In this equation Calcium will displace hydrogen from the acid because it is more reactive, resulting in the formation of CaSO4 (salt), while the displaced H2 molecule combines with OH molecules to form water.

The equation of the reaction is thus;

Ca(OH)2 (aq) + H2SO4 (aq) ----------> CaSO4(aq) + H2O(l), in other to balance it, we add ''2'' to the water molecule in the right hand side of the equation.

Balance equation is

Ca(OH)2 (aq) + H2SO4 (aq) ----------> CaSO4(aq) + 2H2O(l)

You might be interested in

PLEASE HELP ASAP I will mark brainliest

anyanavicka [17]

Answer:

Please explain the question nicely first

6 0

3 years ago

Read 2 more answers

A 40.2 g sample of a metal heated to 99.3Â°C is placed into a calorimeter containing 120 g of water at 21.8Â°C. The final temper

aliina [53]

Answer:

B) Iron (c=0.45 J/g°C)

Explanation:

Given that:-

Heat gain by water = Heat lost by metal

Thus,

$m_{water}\times C_{water}\times (T_f-T_i)=-m_{metal}\times C_{metal}\times (T_f-T_i)$

Where, negative sign signifies heat loss

Or,

$m_{water}\times C_{water}\times (T_f-T_i)=m_{metal}\times C_{metal}\times (T_i-T_f)$

For water:

Mass = 120 g

Initial temperature = 21.8 °C

Final temperature = 24.5 °C

Specific heat of water = 4.184 J/g°C

For metal:

Mass = 40.2 g

Initial temperature = 99.3 °C

Final temperature = 24.5 °C

Specific heat of metal = ?

So,

$120\times 4.184\times (24.5-21.8)=40.2\times C_{metal}\times (99.3-24.5)$

$40.2C_{metal}\left(99.3-24.5\right)=120\times \:2.7\times \:4.184$

$40.2C_{metal}\left(99.3-24.5\right)=1355.616$

$C_{metal}=0.45\ J/g^0C$

<u>This value corresponds to iron. Thus answer is B.</u>

3 0

3 years ago

the decomposition of calcium carbonate to calcium oxide and carbon dioxide only takes place at very high temperatures, making th

USPshnik [31]

So calculate the H for the other two reactions a room temperature and combine the reactions to calculate the H of the decomposition of calcium carbonate using the Hess's Law

4 0

3 years ago

Which of the following actions can a person take in order to best conserve fossil fuel resources?

iris [78.8K]

It’s c it has to be in certain

8 0

3 years ago

Read 2 more answers

Compared to the normal freezing point and boiling point of water, a 1-molar solution of sugar in water will have a

marysya [2.9K]

Answer :

Boiling point of the sugar solution will be higher than that of water's boling point.
Freezing point of the sugar solution will be lower than that of water's freezing point.

Explanation:

Boiling point of a liquid is defined as temperature at which vapor pressure of liquid becomes equal to the atmospheric pressure.

Boiling point of solution is always higher than that of the pure solvent

Vapor pressure increases with increase in temperature which means sugar solution will be heated more to make vapor pressure equal to atmospheric pressure.

Freezing point is defined as temperature at which solid and liquid phase are at equilibrium or temperature at which vapor pressure of liquid becomes equal to the vapor pressure in its solid phase.

Freezing point of solution is always lower than that of the pure solvent.

Lower the temperature, lower will be the vapor pressure which sugar solution solution will get freeze at lower temperature than that of the water.

6 0

3 years ago