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natali 33 [55]
2 years ago
5

A 40-lb container of peat moss measures 14× 20× 30 in. A 40-lb container of topsoil has a volume of 1.9 gal. Calculate the avera

ge density of peat moss in units of g/cm3 .
Chemistry
1 answer:
Viktor [21]2 years ago
8 0

The average density of the peat moss in units of g/cm³ is 2.52 g/cm³

<h3>How to convert 40 lb to grams (g)</h3>

We'lol begin by converting 40 lb to grams (g). This can be obtained as follow:

1 lb = 453.592 g

Therefore,

40 lb = (40 × 453.592) / 1 lb

40 lb = 18143.68 g

<h3>How to convert 1.9 gal to cm³</h3>

We can convert 1.9 gal to cm³ as follow:

1 gal = 3785.41 cm³

Therefore,

1.9 gal = (1.9 gal × 3785.41 cm³) / 1 gal

1.9 gal = 7192.279 cm³

<h3>How to determine the density </h3>

The density can be obtained as follow:

  • Mass = 18143.68 g
  • Volume = 7192.279 cm³
  • Density =?

Density = mass / volume

Density = 18143.68 / 7192.279

Density = 2.52 g/cm³

Learn more about density:

brainly.com/question/952755

#SPJ1

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Rate equation for first order reaction is as follows:

t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}

Here, k is rate constant of the reaction, t is time of the reaction, A_{0} is initial concentration and A_{t} is concentration at time t.

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t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}=\frac{2.303}{0.1 day^{-1}}log\frac{100}{10}=23.03 days

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(b) Let the initial concentration be 100, If 99% of the chemical is destroyed, the chemical present at time t will be 100-99=1, on putting the values,

t=\frac{2.303}{k}log\frac{A_{0}}{A_{t}}=\frac{2.303}{0.1 day^{-1}}log\frac{100}{1}=46.06 days

Thus, time required to destroy 99% of the chemical is 46.06 days.

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