A 40-lb container of peat moss measures 14× 20× 30 in. A 40-lb container of topsoil has a volume of 1.9 gal. Calculate the avera
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Mass of ammonia produced : 121.38 g
<h3>Further explanation</h3>Given
Reaction
3H₂(g) + N₂(g) ⇒ 2NH₃(g)
100g of N₂
Required
Ammonia produced
Solution
mol of N₂ :
From the equation, mol ratio of N₂ and NH₃ = 1 : 2, so mol NH₃ :
mass of NH₃(MW=17 g/mol) :
Answer : The fuel value and the fuel density of pentane is, 49.09 kJ/g and respectively.
Explanation :
Fuel value : It is defined as the amount of energy released from the combustion of hydrocarbon fuels. The fuel value always in positive and in kilojoule per gram (kJ/g).
As we are given that:
Fuel value =
Molar mass of pentane = 72 g/mol
Fuel value =
Fuel value = 49.09 kJ/g
Now we have to calculate the fuel density of pentane.
Fuel density = Fuel value × Density
Fuel density = (49.09 kJ/g) × (0.626g/mL)
Fuel density = 30.73 kJ/mL =
Thus, the fuel density of pentane is