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3 years ago

Which elements, when they have to, can have more than

Chemistry

1 answer:

inn [45]3 years ago

6 0

Elements in the third row can break the octet rule

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The potential in an electrochemical cell, E, is related to the Gibb's free energy change (ΔG) for the overall cell redox reactio

Nana76 [90]

Answer:

Explanation:

As an example, the following cell reaction: Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(m) generates a cell voltage of +1.10 V under standard conditions. Calculate and enter delta G degree (with 3 sig figs) for this reaction in kJ/mol.

Zn(s) + Cu2+(aq) → Zn2+(aq) + Cu(m)

ΔG = ΔG° + RTInQ

Q = 1

ΔG = ΔG°

ΔG = =nFE°

n=no of electrons transfered.

E° = 1.1v

ΔG° = -2 * 96500 * 1.10

= -212300J

ΔG° =-212.3kJ/mol

<h3>Therefore, the ΔG° = -212.3kJ/mol</h3>

5 0

3 years ago

Calculate the number of atoms in 2.5 moles of Si.

Ede4ka [16]

Answer:

$\boxed {\boxed {\sf About \ 1.5 * 10^{24} \ atoms \ Si}}$

Explanation:

When converting from moles to atoms, we must use Avogadro's number. This number tells us there are 6.022 * 10²³ atoms in 1 mole. We can multiply this number by the number of moles.

First, we must set up Avogadro's number as a ratio.

$\frac {6.022 \ * 10^{23} \ atoms \ Si }{1 \ mol \ Si}}$

Next, multiply the number of moles by the ratio.

$2.5 \ mol \ Si *\frac {6.022 \ * 10^{23} \ atoms \ Si }{1 \ mol \ Si}}$

When we multiply, the moles of silicon will cancel.

$2.5 * \frac {6.022 \ * 10^{23} \ atoms \ Si }{1}}$

Since the denominator of the fraction is 1, we can cancel it out too.

$2.5 * {6.022 \ * 10^{23} \ atoms \ Si }$

$1.5055 * 10^{24} \ atoms \ Si$

The original measurement (2.5 moles) has 2 significant figures (2 and 5). Therefore we must round to 2 sig figs. For this question, 2 sig figs is the tenth place.

The 0 in the hundredth place tells us to leave the 5 in the tenth place.

$1.5 * 10^{24} \ atoms \ Si$

There are about <u>1.5 * 10²⁴ atoms of silicon.</u>

7 0

2 years ago

Answer to AP chem question

steposvetlana [31]

Answer:

C4H8

Explanation:

M(CF2) = M(C) + 2M(F) = 12.0 + 2*19.0 = 50.0 g/mol

M(unknown)/M(CF2) = 200.4 g/mol /50.0 g/mol = 4

So we need to take CF2 4 times.

C4H8

7 0

3 years ago

What statement goes against the kinetic theory of gases

Arada [10]

Gas molecules will never collide with the walls of the container

8 0

3 years ago

PLEASE HELP!!!!!!!!!!!!!!!!!!!!!

GREYUIT [131]

They each have one valence electron in their outer shell, but they are also on the same row (period). If you follow this pattern, potassium will also have one valence electron.

Hope this helps!! :)

5 0

2 years ago