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2 years ago

How would you find a fraction of a circle that an arc covers

Mathematics

2 answers:

DaniilM [7]2 years ago

8 0

Answer: It’s divide the measure of the arc by 360 degrees, if I’m not mistaken!

IrinaK [193]2 years ago

3 0

Answer:

Divide the measure of the arc by 180.

Divide the circumference by 360.

Divide the measure of the arc by 360.

Divide the diameter by 360

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The chicken pen held 7 chickens. Each chicken lay 6 eggs a day. How many eggs world they get altogether after 30 days.

Tcecarenko [31]

Answer:

1260 eggs in 30 days

7*6=42

42*30=1260

3 0

1 year ago

Read 2 more answers

I need help on this it’s about trig identities

Cerrena [4.2K]

Answer:

The answer to your question is:

Step-by-step explanation:

1.-

$\frac{1 + sin\alpha }{cos\alpha } + \frac{cos\alpha }{1 + sin\alpha } = 2 sec\alpha$

$\frac{(1 + sin\alpha)^{2} + cos^{2} \alpha }{cos\alpha (1 + sin\alpha) }$

$\frac{1 + 2sin\alpha + sin^{2} \alpha+ cos^{2} \alpha }{cos\alpha + sin\alphacos\alpha }$

$\frac{2 + 2sin\alpha }{cos\alpha+ sin\alpha cos\alpha }$

$\frac{2(1 + sin\alpha) }{cos\alpha(1 + sin\alpha ) }$

$\frac{2}{cos\alpha }$

2sec $\alpha$

2.-

sec²x - tanxsecx

$\frac{1}{cos^{2}x } - \frac{sinx}{cosx} \frac{1}{cosx}$

$\frac{1}{cos^{2} x} - \frac{sinx}{cos^{2}x}$

$\frac{1 - sinx}{cos^{2}x }$

$\frac{1 - sinx}{1 - sin^{2}x }$

$\frac{1 - sinx}{(1 - sinx)(1 + sinx)}$

$\frac{1}{1 + sinx}$

3 0

2 years ago

Find the probability P(not E) if P(E) = 0.43.

Artyom0805 [142]

Answer:

P(not E)= 0.57

Step-by-step explanation:

P(not E)= 1-0.43

P(not E)= 0.57

8 0

2 years ago

At a certain high school, 15 students play stringed instruments and

Aleks [24]

Answer:

0 is the probability that a randomly selected student plays both a stringed and a brass instrument.

Step-by-step explanation:

Given that:

Number of students who play stringed instruments, N(A) = 15

Number of students who play brass instruments, N(B) = 20

Number of students who play neither, N( $A \cup B$ )' = 5

To find:

The probability that a randomly selected students plays both = ?

Solution:

Total Number of students = N(A)+N(B)+N( $A \cup B$ )' =15 + 20 + 5 = 40

(As there is no student common in both the instruments we can simply add the three values to find the total number of students)

As per the venn diagram, no student plays both the instruments i.e.

$N(A\cap B) =0$

Formula for probability of an event E can be observed as:

$P(E) = \dfrac{\text{Number of favorable cases}}{\text {Total number of cases}}$

$P(A\cap B) = \dfrac{N(A\cap B)}{N(U)}\\\Rightarrow \dfrac{0}{40}\\\Rightarrow P(A\cap B) = 0$

So, 0 is the probability that a randomly selected student plays both a stringed and a brass instrument.

5 0

2 years ago

What I'd the answer to this? please help me guys!

sp2606 [1]

Knowing the fractions increase, the arrow should be pointing to 5/8.

Hope it helped,

Happy homework/ study/ exam!

5 0

2 years ago

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