Answer:
67
Step-by-step explanation:
Multi-Inscribed Quadrilateral: 15
Bananas: 4
Clock: 3
Therefore, we can substitute for the last equation the values, so it would become:
3 + 4 + 4 x 15 = ?
First, we solve the multiplication according to PEMDAS.
4 x 15 = 60
Then, we can add from left to right.
3 + 4 + 60 = ?
3 + 4 = 7
7 + 60 = 67
Therefore, our answer would be 67.
Answer:
x = −
4
Step-by-step explanation:
Answer:
The answer is below
Step-by-step explanation:
The Angle Addition Postulate states that the measure of an angle formed by two or more angles which are placed side by side is the sum of the measures of the two angles.
Therefore:
∠MON = ∠MOP + ∠NOP (angle addition postulate)
Substituting values gives:
124 = (2x + 1) + (2x + 1)
124 = 2x + 2x + 1 + 1
124 = 4x + 2
subtracting 2 from both sides of the equation:
124 - 2 = 4x + 2 - 2
4x = 122
Dividing through by 4:
4x / 4 = 122 / 4
x = 30.5
Therefore ∠MOP = 2x + 1 = 2(30.5) + 1 = 62°, ∠NOP = 2x + 1 = 2(30.5) + 1 = 62°
∠MOP = 62°, ∠NOP = 62°
1. Given any triangle ABC with sides BC=a, AC=b and AB=c, the following are true :
i) the larger the angle, the larger the side in front of it, and the other way around as well. (Sine Law) Let a=20 in, then the largest angle is angle A.
ii) Given the measures of the sides of a triangle. Then the cosines of any of the angles can be found by the following formula:

2.

3. m(A) = Arccos(-0.641)≈130°,
4. Remark: We calculate Arccos with a scientific calculator or computer software unless it is one of the well known values, ex Arccos(0.5)=60°, Arccos(-0.5)=120° etc
The formula of an area of a square:

a - a side
We have 
substitute:

Used:
