If we take a look at the phylogenetic tree of bears presented in the picture above, we can see that the branch number one is the common ancestor to all living bear species, which means that the whole group has a uniform origin. and the
phylogenetic tree has a root. Therefore, the group is monophyletic, not <span>polyphyletic ( meaning that the whole group has the same origin) and not paraphyletic ( there is no group that has been excluded from the tree).</span>
<span>Joints with no movement are called immoveable or fibrous joints.They are also called synathrosis, they are only separated by a thin layer of fibrous connective tissue e.g are the sutures of the skull.
Joints that are more loosely connected are called freely moveable or synovial joints. They are also called diarthrosis.The joints are held together by an articular capsule comprised of ligaments. A synovial membrane lines the inside of the capsule and secretes synovial fluid which lubricates the joint (hence it's name).</span>
<span>A scientific theory must be testable and capable of being proven false. This is very important for these theories to be dealt with because they become the dependencies when they are applied for the analysis of the concepts and problem solving.</span>
Answer:
The Wood
Explanation:
The wood has the most friction because the final speed is less than the others when the fan is on and the cart slowed down the fastest when the fan is turned off.
Answer:
1500
Explanation:
Let's assume that the allele for yellow seed color is "Y" and the allele for green seed color is "y". Genotype of pure breeding yellow seeded plant would be "YY" and that of the green seeded plant would be "yy". A cross between YY and yy gives all heterozygous yellow seeded plants (Yy) in F1 progeny. Self pollination of two F1 plants (Yy x Yy) obtains F2 generation in 3 yellow: 1 green ratio.
The total population size of F2 generation = 2000
The proportion of yellow seeded plants in F2 generation = 3/4 (since the F2 phenotype ratio is given 3 yellow: 1 green)
Therefore, total number of yellow seeded plants in F2 progeny = 3/4 x 2000= 1500
