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Finger [1]
3 years ago
13

A small omnidirectional stereo speaker produces waves in all directions that have an intensity of 6.5 w/m^2 at a distance of 2.5

m from the speaker. At what rate does this speaker produce energy?
Physics
1 answer:
Anna007 [38]3 years ago
6 0

Answer:

the rate at which the speaker produces energy is 510.51 J/s

Explanation:

Given;

sound intensity of the speaker, I = 6.5 W/m²

distance, r = 2.5 m

The rate at which the speaker produces energy on a spherical surface is given as;

P = IA

P = I(4πr²)

P = 6.5 (W/m²) x 4π x (2.5 m)²

P = 510.51 J/s

Therefore, the rate at which the speaker produces energy is 510.51 J/s

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A tube 1.20 m long is closed at one end. A stretched wire is placed near the open end. The wire is 0.350 m long and has a mass o
Ksju [112]

Answer:

71.4583 Hz

67.9064 N

Explanation:

L = Length of tube = 1.2 m

l = Length of wire = 0.35 m

m = Mass of wire = 9.5 g

v = Speed of sound in air = 343 m/s

The fundamental frequency of the tube (closed at one end) is given by

f=\frac{v}{4L}\\\Rightarrow f=\frac{343}{4\times 1.2}\\\Rightarrow f=71.4583\ Hz

The fundamental frequency of the wire and tube is equal so he fundamental frequency of the wire is 71.4583 Hz

The linear density of the wire is

\mu=\frac{m}{l}\\\Rightarrow \mu=\frac{9.5\times 10^{-3}}{0.35}\\\Rightarrow \mu=0.02714\ kg/m

The fundamental frequency of the wire is given by

f=\frac{1}{2l}\sqrt{\frac{T}{\mu}}\\\Rightarrow f^2=\frac{1}{4l^2}\frac{T}{\mu}\\\Rightarrow T=f^2\mu 4l^2\\\Rightarrow T=71.4583^2\times 0.02714\times 4\times 0.35^2\\\Rightarrow T=67.9064\ N

The tension in the wire is 67.9064 N

7 0
3 years ago
Liam is two-years old. His mother is concerned about his behavior. Liam is very different from how his sister Briana was when sh
slavikrds [6]

Answer:

Autism

Explanation:

Those are some symptoms of autism that you described

5 0
3 years ago
What is moral science?
Lelu [443]

Moral science is social sciences or philosophy.


That's it, really!


5 0
4 years ago
The following three questions refer to a situation in which a driver is in a car that crashes into a solid wall. The car comes t
Andreas93 [3]

Answer:

1) p₀ = 45000 N / s ,   p₀ '= 1800 , b)  I = -45000 N s ,  I = 1800 Ns

Explanation:

Impulse equals the change in momentum

         I = Δp

1) the initial moment of the car

         p₀ = M v

          p₀ = 1500 30

          p₀ = 45000 N / s

the change at the moment is

          Δp = 45000

because the end the car is stopped

moment of the person

          P₀ ’= m v

         p₀ '= 60 30

          p₀ '= 1800

          D₀ '= 1800

2) of the momentum change impulse ratio

        car

              I =  Δp

              I = -45000 N s

        person

              I = Δpo '

              I = 1800 Ns

3) the object that give the momentum to stop the wall motoring

The person is stopped by the impulse given by the car

a) This area is the one that absorbs most of the vehicle impulse

be) If using a safety painter, the time during which the greater force will act, therefore the lessons decrease

c) The air bag helps reduction in the speed of the person relatively quickly.

6 0
4 years ago
In measuring the width of a hair sample, a light of wavelength 500 nm is used. The hair sample is 40 um in radius. With the scre
sergejj [24]

Answer:

The distance of the second dark band away from the central bright spot be located is 5.625\times10^{-2}\ m

Explanation:

Given that,

Wave length = 500 nm

Radius d= 40\ \mu m

Distance from the hair sample D= 6 m

We need to calculate the distance of the second dark band away from the central bright spot be located

\sin\theta=\dfrac{y}{D}

\sin\theta=\dfrac{y}{6}

Using formula for dark fringe

(n-\dfrac{1}{2})\lambda=2d\sin\theta

Put the value into the formula

(2-\dfrac{1}{2})\times500\times10^{-9}=2\times40\times10^{-6}\times\dfrac{y}{6}

y=\dfrac{(2-\dfrac{1}{2})\times500\times10^{-9}\times6}{2\times40\times10^{-6}}

y=0.05625\ m

y=5.625\times10^{-2}\ m

Hence, The distance of the second dark band away from the central bright spot be located is 5.625\times10^{-2}\ m

6 0
3 years ago
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