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Finger [1]
3 years ago
13

A small omnidirectional stereo speaker produces waves in all directions that have an intensity of 6.5 w/m^2 at a distance of 2.5

m from the speaker. At what rate does this speaker produce energy?
Physics
1 answer:
Anna007 [38]3 years ago
6 0

Answer:

the rate at which the speaker produces energy is 510.51 J/s

Explanation:

Given;

sound intensity of the speaker, I = 6.5 W/m²

distance, r = 2.5 m

The rate at which the speaker produces energy on a spherical surface is given as;

P = IA

P = I(4πr²)

P = 6.5 (W/m²) x 4π x (2.5 m)²

P = 510.51 J/s

Therefore, the rate at which the speaker produces energy is 510.51 J/s

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The lung capacity of the average adult is 5.5 liters at the surface and only .37 liters at a depth of 100 meters. The formula to
Alika [10]
I think you can just sub the values in? unless the qn is asking for smth else?

4 0
3 years ago
Roller coasters accelerates from initial speed of 6.0 M/S2 final speed of 70 M/S over four seconds. What is the acceleration?
choli [55]

Answer:

a=16\ m/s^2

Explanation:

<u>Motion With Constant Acceleration </u>

It's a type of motion in which the velocity of an object changes uniformly in time.

The formula to calculate the change of velocities is:

v_f=v_o+at

Where:

a   = acceleration

vo = initial speed

vf  = final speed

t    = time

The roller coaster moves from vo=6 m/s to vf=70 m/s in t=4 seconds. To calculate the acceleration, solve for a:

\displaystyle a=\frac{v_f-v_o}{t}

\displaystyle a=\frac{70-6}{4}=\frac{64}{4}

\boxed{a=16\ m/s^2}

3 0
3 years ago
Suppose our experimenter repeats his experiment on a planet more massive than Earth, where the acceleration due to gravity is g
Ne4ueva [31]

Answer:

C

Explanation:

- Let acceleration due to gravity @ massive planet be a = 30 m/s^2

- Let acceleration due to gravity @ earth be g = 30 m/s^2

Solution:

- The average time taken for the ball to cover a distance h from chin to ground with acceleration a on massive planet is:

                                 t = v / a

                                 t = v / 30

- The average time taken for the ball to cover a distance h from chin to ground with acceleration g on earth is:

                                 t = v / g

                                 t = v / 9.81

- Hence, we can see the average time taken by the ball on massive planet is less than that on earth to reach back to its initial position. Hence, option C

7 0
3 years ago
A bat moving at 3.7 m/s is chasing a ying insect. The bat emits a 36 kHz chirp and receives back an echo at 36.79 kHz. At what s
3241004551 [841]

Answer:

The speed the bat is gaining on its prey is 0.03m/s

Explanation:

Given;

speed of the bat, v₀ = 3.7 m/s

frequency of the bat, F₀ = 36 kHz

frequency of the source, Fs = 36.79

This is relative motion between a source of the sound and the observer.  The phenomenon is known as Doppler effect.

Apply the following equation to determine the speed of the insect which is the source;

F_0 = F_s[\frac{v+v_0}{v-v_s} ]\\\\\frac{F_0}{F_s} = [\frac{v+v_0}{v-v_s} ]\\\\\frac{36.79}{36} = \frac{340+3.7}{340-v_s}\\\\1.0219 = \frac{343.7}{340-v_s}\\\\  340-v_s = \frac{343.7}{1.0219}\\\\340-v_s = 336.33\\\\v_s = 340-336.33\\\\v_s = 3.67 \ m/s

The speed the bat is gaining on its prey = 3.7m/s - 3.67m/s = 0.03 m/s

Therefore, the speed the bat is gaining on its prey is 0.03m/s

8 0
3 years ago
A 20,000 kg railroad car is traveling at 5 m/s when it collides and couples with a second, identical car at rest. What is the re
PilotLPTM [1.2K]
Ok I don’t know the answer I’m in 5th grade but 2431 is wrong
7 0
3 years ago
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