A :-) F = ma 
Given - m = 95 kg 
 a = 2.2 m/s^2 
Solution - 
F = ma 
F = 95 x 2.2 
F = 209 
.:. The force is 209 N
        
             
        
        
        
<h2>
Its velocity when it crosses the finish line is 117.65 m/s</h2>
Explanation:
We have equation of motion s = ut + 0.5 at²
         Initial velocity, u = 0 m/s
         Acceleration, a = ?
         Time, t = 6.8 s    
         Displacement, s = 1/4 mi =    400 meters
      Substituting
                       s = ut + 0.5 at²
                       400 = 0 x 6.8 + 0.5 x a x 6.8²
                       a = 17.30 m/s²
Now we have equation of motion v = u + at
      Initial velocity, u = 0 m/s
      Final velocity, v = ?
      Time, t = 6.8 s
       Acceleration, a = 17.30 m/s²
      Substituting
                       v = u + at  
                       v = 0 + 17.30 x 6.8
                       v = 117.65 m/s
Its velocity when it crosses the finish line is 117.65 m/s
 
        
             
        
        
        
Explanation:
Assuming the wall is frictionless, there are four forces acting on the ladder.
Weight pulling down at the center of the ladder (mg).
Reaction force pushing to the left at the wall (Rw).
Reaction force pushing up at the foot of the ladder (Rf).
Friction force pushing to the right at the foot of the ladder (Ff).
(a) Calculate the reaction force at the wall.
Take the sum of the moments about the foot of the ladder.
∑τ = Iα
Rw (3.0 sin 60°) − mg (1.5 cos 60°) = 0
Rw (3.0 sin 60°) = mg (1.5 cos 60°)
Rw = mg / (2 tan 60°)
Rw = (10 kg) (9.8 m/s²) / (2√3)
Rw = 28 N
(b) State the friction at the foot of the ladder.
Take the sum of the forces in the x direction.
∑F = ma
Ff − Rw = 0
Ff = Rw
Ff = 28 N
(c) State the reaction at the foot of the ladder.
Take the sum of the forces in the y direction.
∑F = ma
Rf − mg = 0
Rf = mg
Rf = 98 N
 
        
             
        
        
        
Here are the planets listed in order of their distance from the Sun: Mercury, Venus, Earth, Mars, Jupiter, Saturn, Uranus, and Neptune. An easy mnemonic for remembering the order is “My Very Educated Mother Just Served Us Noodles
Hope this helps.
        
             
        
        
        
Answer:
The focal length of the lens should be -51.5 cm (a concave lens).
Explanation:
The purpose of the lens is to make objects at 48.5 cm appear at the healthy near point. The healthy near point is 25.0 cm.
We use the lens formula

where <em>f</em> = focal length, <em>u</em> = object distance and <em>v</em> = image distance.
In this case, <em>u</em> = 48.5 cm and <em>v</em> = -25.0 cm.
<em>v</em> is negative because the image is virtual an not real. (Here, we are using the real-is-positive sign convention)


The negative sign indicates the lens is concave.