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Tresset [83]
3 years ago
8

What is the correct equation for calculating kinetic energy?

Physics
1 answer:
inna [77]3 years ago
6 0

Answer:

2. kinetic energy = total energy - potential energy

Explanation:

The total energy of a system is the addition of kinetic and potential energy of the system. Kinetic energy can be regarded as form of energy posses by an object when it's in motion

Total energy = kinetic energy + potential energy

(If we make Kinectic energy the subject of the formula, we have)

kinetic energy = total energy - potential energy

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Unexpected orbital velocities of stars around the centers of galaxies led astronomers to predict the existence of dark _____.
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Susan goes out to exercise. She runs for one hour at a constant speed and velocity. What is the overall net force acting on Susa
kiruha [24]

Option (A ) is correct.

Explanation:

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Consider a machine of mass 70 kg mounted to ground through an isolation system of total stiffness 30,000 N&gt;m, with a measured
kvv77 [185]

Answer:

a)0.0229 m

b)0.393 rad

c)1.57

d)707.6 N

e)0.298 m/s

Explanation:

Given:

  • Mass of the machine, m=70 kg
  • Stiffness of the system, k=30000 N/m
  • Damping ratio=0.2
  • Damping force, F=450 N
  • Angular velocity \omega=13\ \rm rad/s

a)We know that the amplitude X at steady state is given by

X=\dfrac{\dfrac{F_0}{m}}{\sqrt{\omega_n^2-\omega^2)^2 +(2\rho \omega_n\omega)^2}}\\

Where

  • \omega_n=\sqrt{\dfrac{k}{m}}\\\\=\sqrt{\dfrac{30000}{70}}\\\\=20.7\ \rm rad/s
  • \omega=13\ \rm rad/s
  • \rho=0.2
  • F_0=450\ \rm N
  • m=70\ \rm kg

X=\dfrac{\dfrac{450}{70}}{\sqrt{20.7^2-13^2)^2 +(2\times 0.2\times20.7\times13)^2}}\\[tex]X=0.0229\ \rm m

b) The phase shift of the motion is given by

\tan\phi=\dfrac{2\rho \omega_n \omega }{\omega_n^2-\omega^2}\\\\\dfrac{2\times0.2\times20.7\times13 }{20.7^2-\13^2}\\\\\phai=0.393\\

c)Transmissibility ratio is given by

T.R.=\sqrt{\dfrac{1+(2\rho r)^2}{(1-r^2)^2+{(2\rho r)^2}}}\\\\T.R.=\sqrt{\dfrac{1+(2\times0.2\times0.628)^2}{(1-0.628^2)^2+{(2\times0.2\times0/628)^2}}}\\\\=1.57

d)The magnitude of the force transmitted to the ground is

F_T=(T.R)\times F_0\\\\=450\times1.57\\\\=707.6\ \rm N

e)The maximum velocity is given by V_{max}

V_{max}=\omega A_0\\\\=13\times 0.0229\\\\=0.298\ \rm m/s

6 0
3 years ago
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