A Formula 1 racing car can accelerate from a stationary position to 25 m/S in 2.1s calculate
1 answer:
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Answer:
Explanation:
Notice that this is a circuit with resistors R1 and R2 in parallel, connected to resistor R3 in series. It is what is called a parallel-series combination.
So we first find the equivalent resistance for the two resistors in parallel:
By knowing this, we can estimate the total current through the circuit,:
So approximately 0.17 amps
and therefore, we can estimate the voltage drop (V3) in R3 uisng Ohm's law:
So now we know that the potential drop across the parellel resistors must be:
10 V - 4.28 V = 5.72 V
and with this info, we can calculate the current through R1 using Ohm's Law:
Answer:
number of cycles = 4.68 × 10⁴ cycles
Explanation:
In damped RLC oscillation
voltage (V(t)) = V_o\ e^{-\dfrac{tR}{2L}}............(1)
given,
C = 0.17μF = 0.17 × 10⁻⁶ F
R = 1.4 Ω
L = 15 m H = 15 × 10⁻³ H V(t) = V₀/2
From the equation (1)
taking log both side
t = 14.85 sec
time period
T = 3.172 × 10⁻⁴
number of cycle =
=
number of cycles = 4.68 × 10⁴ cycles