Answer:
Point slope form
y - 9 = 4(x-1)
Equation of the straight line passing through the point (1,9) and slope 'm' = 4 is 4 x - y +5=0
Step-by-step explanation:
<u><em>Step(i):-</em></u>
Given that the points are (1,9) and (-1,1)
slope of the line
m = 
m = 4
<u><em>step(ii):-</em></u>
Equation of the straight line passing through the point (1,9) and slope 'm' = 4
y-y₁ = m( x-x₁)
y - 9 = 4(x-1)
y -9 = 4x-4
4 x - y -4+9 =0
4 x - y +5=0
Equation of the straight line passing through the point (1,9) and slope 'm' = 4 is 4 x - y +5=0
<h2>1 way</h2>
For 20 shirts Eric has
20×2=40 ties
After shopping Eric has 50 shirts
So
20 shirts 50 shirts
40 ties x ties
Answer: He would have 100 ties
<h2>2 way</h2>
If he has 2 ties for 1 shirt he will have
2×20=40 ties for 20 shirts, so for 50 shirts ge would have
50×2=100 ties
Answer: He would have 100 ties
Answer:
Step-by-step explanation:
Let's look at what 10^100 and 100^10 are as numbers without exponents.
Ten raised to a positive integer exponent is a 1 followed by the number of zeros the exponent tells you. For example, 10^2 is 100, or 1 followed by 2 zeros, just like the exponent 2 tells you. 10^5 is 1 followed by 5 zeros, or 100,000. A googol is 10^100 which is a 1 followed by 100 zeros.
Let's use rules of exponents to understand what 100^10 is.
100^10 = (10^2)^10
To raise a power to a power, multiply powers.
100^10 = (10^2)^10 = 10^20
We know what 10^20 means. It is a 1 followed by 20 zeros.
A googol, 10^100, is a 1 followed by 100 zeros.
100^10 is the same as 10^20 or 1 followed by 20 zeros.
A googol is much, much greater than 100^10.
Answer:
Correct option is
C
36.25
Modal class =30−40
So we have, l=30,f0=12,f1=32,f2=20 and h=10
⇒ Mode=l+2f1−f0f2f1−f0×h
=30+2×32−12−2032−12×10
=30+6.25
=36.25
∴ Mode =36.25
Answer:
Teresa tiene 1 chocolate.
Ella le da 1/3 del chocolate a Miguel, entonces ahora Teresa tendrá un chocolate menos un tercio de chocolate, es decir, ella tiene:
1 - 1/3 = 3/3 - 1/3 = 2/3 de un chocolate.
Ahora le da 1/4 a diego, entonces lo que le sobra va a ser:
2/3 - 1/4
recordar que tenemos que tener el mismo denominador en ambas fracciones, entonces podemos reescribir esto como:
(4/4)*(2/3) - (3/3)*(1/4)
(a cada fracción la multiplico y divido por el denominador de la otra)
8/12 - 3/12 = (8 - 3)/12 = 5/12
Es decir, Teresa finalmente tiene 5/12 del chocolate.
Entonces la parte de chocolate que repartió es lo que le falta, que se obtiene como:
1 - 5/12 = 12/12 - 5/12 = 7/12
Ella repartió 7/12 de su chocolate.
