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3 years ago

URGENT PLEASE HELP

Mathematics

1 answer:

Kaylis [27]3 years ago

7 0

Answer:

Step-by-step explanation:

taking a hot guess off of the info I found on the internet and some math, good luck though

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NEED HELP, REALLY URGENT!! Will mark Brainliest for the right answer!!!

Flauer [41]

Answer:

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Step-by-step explanation:

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3 years ago

Plz help me with this problem

mixer [17]

I don’t know what is your problem is

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4 years ago

Evaluate 4b-3c-7 for b=4 and c=1

Alex

The answer is 8

Happy studying!

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3 years ago

Read 2 more answers

Simplify the expression cos x cot x+ sin x please select the best answer from the choices provided a.0, b.csc x, c. Tan x, d sec

expeople1 [14]

Answer:

$cot x = \frac{cos x}{sin x}$

$cos x \frac{cos x}{sin x} + sin x$

$\frac{cos^2 x}{sin x} +sin x$

$sin^2 x + cos^2 x =1$

Solving for $cos^2 x$ we got $cos^2 x =1 -sin^2 x$ and replacing this we got:

$\frac{1-sin^2 x}{sin x} +sin x$

$\frac{1}{sin x} -\frac{sin^2 x}{sin x} +sin x$

$csc x -sin x + sin x = csc x$

And then the best option for this case would be:

b.csc x

Step-by-step explanation:

For this case we have the following expression given:

$cos x cot x + sin x$

We know from math properties that the definition for cot is $cot x = \frac{cos x}{sin x}$

If we use this definition we got:

$cos x \frac{cos x}{sin x} + sin x$

$\frac{cos^2 x}{sin x} +sin x$

Now we can use the following identity:

$sin^2 x + cos^2 x =1$

Solving for $cos^2 x$ we got $cos^2 x =1 -sin^2 x$ and replacing this we got:

$\frac{1-sin^2 x}{sin x} +sin x$

$\frac{1}{sin x} -\frac{sin^2 x}{sin x} +sin x$

$csc x -sin x + sin x = csc x$

And then the best option for this case would be:

b.csc x

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4 years ago

placing 12 tiles side by side, Pete can make a 12-by-1 rectangle. Name two other rectangles Pete can make with 12 tiles

sweet [91]

6x2
3x4
.............................

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4 years ago