Answer:
x = 6/11
Step-by-step explanation:
2(-3x + 4 ) = 5x + 2
-6x + 8 = 5x + 2
- 2 - 2
-6x + 6 = 5x
+6x +6x
6 = 11x
/11 /11
6/11 = x
The function you seek to minimize is
()=3‾√4(3)2+(13−4)2
f
(
x
)
=
3
4
(
x
3
)
2
+
(
13
−
x
4
)
2
Then
′()=3‾√18−13−8=(3‾√18+18)−138
f
′
(
x
)
=
3
x
18
−
13
−
x
8
=
(
3
18
+
1
8
)
x
−
13
8
Note that ″()>0
f
″
(
x
)
>
0
so that the critical point at ′()=0
f
′
(
x
)
=
0
will be a minimum. The critical point is at
=1179+43‾√≈7.345m
x
=
117
9
+
4
3
≈
7.345
m
So that the amount used for the square will be 13−
13
−
x
, or
13−=524+33‾√≈5.655m
The value of (f-g)(144) is 0
Step-by-step explanation:
We are given:
We need to find value of (f-g)(144)
We will put x=144 for both f(x) and g(x)
So, the value of (f-g)(144) is 0
Keywords: Composite Functions
Learn more about Composite Functions at:
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