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3 years ago

In the figure, the shaded region is formed by removing a circle of centre P and radius 5 cm

Mathematics

1 answer:

S_A_V [24]3 years ago

7 0

$\large\boxed{\fcolorbox{red}{aqua}{Radius~of~semi~circle~=~10cm}}$

$\large\underline\mathrm\purple{Diameter~is~20cm}$

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Superman and Spider-Man take turns in saving the world in the ratio of 4:3. There are 42 disastrous events , how many times do t

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42 times

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3 years ago

If s = 1 over 4 unit and A = 80s2, what is the value of A, in square units? square unit(s). (Input whole number only.) (1 point)

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2 years ago

a pyramid whose altitude is 5ft weighs 800lbs. at what distance from its vertex must it be cut by a plane parallel to its base s

slavikrds [6]

A structure which has a square base and four triangular sides meeting at a point is called pyramid.

At distance of 3.97 feet from its vertex , pyramid is cut by plane so that the two solids of equal weight will be formed.

<u>It is assumed that weight of pyramid is proportional to its volume.</u>

So, $w = k V$ , where V is volume of original pyramid and v is volume of small pyramid and k is constant.

Let us consider that at h distance, pyramid is cut from its vertex. So a small pyramid is also formed.

Assume that base area of original pyramid is A and base of small pyramid is a.

Volume of original pyramid is, $V= \frac{1}{3} *A* 5$

So, weight of original pyramid, $W = k *(\frac{1}{3} *A* 5) = 800$

Volume of small pyramid is, $v = \frac{1}{3}* a* h$

So, weight of small pyramid, $w = k*(\frac{1}{3}* a* h)=400$

<u>Since, base and height of small pyramid and original pyramid are in proportion.</u>

So, $\frac{a}{A} = (\frac{h}{5}) ^{2}$

$a = (\frac{h}{5} )^{2}A$

Substituting value of a in equation $k*(\frac{1}{3}* a* h)=400$

So, $k*(\frac{1}{3}* \frac{h^{2} }{25}A * h)=400$

$(k*\frac{1}{3}* A*5)*\frac{1}{5} *\frac{h^{2} }{25} * h)=400$

Since, $(k *\frac{1}{3} *A* 5) = 800$ , substitute in above equation.

So, $800*\frac{h^{3} }{125}=400\\\\h^{3}=\frac{125}{2}\\\\h=\sqrt[\frac{1}{3} ]{62.5}\\\\h=3.97 feet$

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2 years ago

Read 2 more answers

The endpoints of one side of a regular pentagon or -1, four and two, three what is the perimeter of the Pentagon

forsale [732]

Answer:

Step-by-step explanation:

$(-1,4),(2,3)\\ \\ s^2=(-1-2)^2+(4-3)^2\\ \\ s^2=9+1\\ \\ s^2=10\\ \\ s=\sqrt{10}\\ \\ p=5s\\ \\ p=5\sqrt{10}\ exact\\ \\ p\approx 15.8$

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2 years ago

Solve these equations. Thanks.

Nutka1998 [239]

Answer:

1. 3.572 x 10^(-1)

2. 3.108 x 10^(6)

3. 5.31881533 x 10^(-6)

4. 4.18676122 x 10^(-1)

Hope this helps

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2 years ago