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anastassius [24]
3 years ago
12

In the figure, the shaded region is formed by removing a circle of centre P and radius 5 cm

Mathematics
1 answer:
S_A_V [24]3 years ago
7 0
<h2>___________________</h2>

\large\boxed{\fcolorbox{red}{aqua}{Radius~of~semi~circle~=~10cm}}

\large\underline\mathrm\purple{Diameter~is~20cm}

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1. Write the linear equation for a line with a slope of 1/2 that goes through the point (-1,<br> 0).
svetlana [45]

Answer:

uhuhhubuggyugyug

uiyuyuh

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Step-by-step explanation:

y7gukgyfkjiyfikyutgikuygtujki

6 0
2 years ago
Please help and explain how to do this
Mnenie [13.5K]

Answer:

  4√3

Step-by-step explanation:

The distance formula applies. It tells you ...

  distance = √((x2 -x1)² +(y2 -y1)²)

Filling in the given values, you have ...

  distance = √((-√32 -(-4√2))² +(2√3 -(-√12))²)

  = √((-4√2+4√2)² +(2√3 +2√3)²)

  = √(0 + (4√3)²)

  distance = 4√3

___

We make use of the fact that ...

  a\sqrt{b}=\sqrt{a^2b}\\\\\sqrt{32}=\sqrt{16\cdot 2}=4\sqrt{2}\\\\2\sqrt{3}=\sqrt{2^2\cdot 3}=\sqrt{12}

3 0
2 years ago
Help PLEASE I don't get this giving many points
Tom [10]

Answer:

x=20

Step-by-step explanation:

7 0
3 years ago
The 2003 Zagat Restaurant Survey provides food, decor, and service ratings for some of the top restaurants across the United Sta
earnstyle [38]

Answer:

The probability that none of the meals will exceed the cost covered by your company is 0.2637.

Step-by-step explanation:

A hyper-geometric distribution is used to define the probability distribution of <em>k</em> success in <em>n</em> samples drawn from a population of size <em>N</em> which include <em>K</em> success. Every draw is either a success of failure.

The random variable <em>X</em> = number of meals that will exceed the cost covered by the company.

The random variable <em>X</em> follows a hyper-geometric distribution.

The information provided is:

N = 15

K = 3

n = 5

k = 0

The probability mass function of a hyper-geometric distribution is:

P(X=k)=\frac{{K\choose k}{N-K\choose n-k}}{{N\choose n}}

Compute the probability that none of the meals will exceed the cost covered by your company as follows:

P(X=0)=\frac{{3\choose 0}{15-3\choose 5-0}}{{15\choose 5}}=\frac{1\times 792}{3003}=0.2637

Thus, the probability that none of the meals will exceed the cost covered by your company is 0.2637.

3 0
3 years ago
Question 4
lukranit [14]

Answer:

Mrs.Harper bought 87.3 key chains which rounds up to 240.075

Step-by-step explanation:

5 0
2 years ago
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