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anastassius [24]

3 years ago

12

In the figure, the shaded region is formed by removing a circle of centre P and radius 5 cm

1 answer:

S_A_V [24]3 years ago

7 0

<h2>___________________</h2>

$\large\boxed{\fcolorbox{red}{aqua}{Radius~of~semi~circle~=~10cm}}$

$\large\underline\mathrm\purple{Diameter~is~20cm}$

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Help me on this questions please.

Pepsi [2]

Answer:

The formula for exponential growth is f(x)=a(1+r)^x, where a is the initial amount/number, r is the growth rate, and x is the number of years/month/etc. The problem tells us that the initial area is 4500. Every year, it decreases by 7.25%, which is technically -0.0725. "t" is the time. Therefore, we plug in those values into the formula. Then, we have:

f(x) = 4500(1-0.0725)^t

f(x) = 4500(0.9275)^t.

4 0

3 years ago

Each big square below represents one whole. What percent is represented by the shaded area

RSB [31]

Total: 160, Left:100 Right:60

4 0

2 years ago

A2+B2B=c2 what is the value of a2

igor_vitrenko [27]

The value of a2 will be I dont care

4 0

3 years ago

PLEEASE HELP TIMED!!!!

elixir [45]

Question 1: Option B: $y=\frac{1}{3}x -2$

Question 2: Option D: $y+1=3 (x+1)$

Solution:

Question 1:

The point on the given line are (2, 4) and (4, –2).

Slope of the given line:

$$m=\frac{y_2-y_1}{x_2-x_1}$

$$m=\frac{-2-4}{4-2}$

m = –3.

Slope of perpendicular line = –1 ÷ Slope of the given line

Slope of perpendicular line = $\frac{1}{3}$

Perpendicular line passing through the point (3, 1).

Slope -intercept form using point slope formula,

$y-y_1=m(x-x_1)$

$y-1=\frac{1}{3} (x-3)$

$y-1=\frac{1}{3} x-1$

$y=\frac{1}{3}x -2$

Option B is the correct answer.

Question 2:

The point on the given line are (0, –3) and (2, 3).

Slope of the given line:

$$m=\frac{3+3}{2-0}$

$$m=\frac{6}{2}$

m = 3.

Slope of parallel lines are equal.

Slope of parallel line =3

parallel lines passing through the point (–1, –1).

Point slope formula:

$y-y_1=m(x-x_1)$

$y+1=3 (x+1)$

Option D is the correct answer.

6 0

3 years ago

Read 2 more answers

Given the functions f(x) = 3x and g(x) = x² + 1, find [(gºf)(x)]- [(fºg)(x)].

Ipatiy [6.2K]

Answer:

6x^2 - 2

Step-by-step explanation:

plug in f(x) into the g(x) formula given

g(f(x)) = (3x)^2 + 1

simplify

= 9x^2+2

plug in g(x) into the f(x) formula given

f(g(x)) = 3(x^2+1)

distribute

= 3x^2 +3

set g(f(x)) - f(g(x))

(9x^2+2) - (3x^2+3)

carry the negative

9x^2+2-3x^2-3

simplify by combining like terms

6x^2-2

7 0

3 years ago