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satela [25.4K]
3 years ago
15

35 to 77 simplified is

Mathematics
1 answer:
polet [3.4K]3 years ago
5 0

Answer:

5/11

Step-by-step explanation:

35 to 77 simplified is 5/11

35 ÷ 7

---------

77 ÷ 7

Therefore, 35/77 simplified to lowest terms is 5/11.

Hope that helps

And if wrong sorry

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If f (x) = -12x + 34 What is the value of f (-2)?
kobusy [5.1K]

Answer:

f(-2)=58

Step-by-step explanation:

f(x)=-12x+34

f(-2)=-12(-2)+34

f(-2)=24+34

f(-2)=58

7 0
2 years ago
Which value of h makes the equation below true?<br> 5x + 8 = 28
GenaCL600 [577]

Answer:

Step-by-step explanation:

So, the point of this is to make x the only thing on one side, so we can see what x is!

Okay so first subtract 8 on both sides...

5x= 25

Now we need to divide on both sides!

That equals...

x=5

So now we know that x=5!

Hope this helped!! :D

If you have any questions whatsover, make sure to comment!

4 0
3 years ago
Read 2 more answers
Two truckers leave from the same point driving in opposite​ directions, the first trucker driving at 62 miles per hour and the s
Elodia [21]

Answer:

1 hour 42 minutes

Step-by-step explanation:

Given: Speed of 1st trucker= 62 mph

           Speed of 2nd trucker= 66 mph

           Total distance need to cover to be in contact is 270 miles

           1st trucker start 1 hour ahead of 2nd trucker

Lets assume 2nd trucker take `x` hours to be in contact and 1st trucker take `(x+1)` hours.

We know, distance= speed\times time

1st trucker, distance(d_1)= 62\times (x+1)

                     ∴ d_1= 62x+62

2nd trucker, distance(d_2)= 66\times x

                    ∴d_2= 66x

Now, putting the values in an equation.

d_1+d_2= 270

⇒ (62x+62)+66x= 270

Opening the parenthesis to solve and subtracting both side by 62

⇒ 122x= 208

∴ x= \frac{208}{122} = 1.70\ h = 1 hour 42 minutes

∴ It will take 1 hour 42 minutes to be able contact each other after first trucker leaves.

3 0
3 years ago
Help I’m not sure with this one!! Urgent help
Nastasia [14]

This system has exactly one solution, because the two equation are linearly independent (i.e. one is not a multiple of the other).

We can explicitly find the solutions: from the first equation we deduce

x = \dfrac{c-by}{a}

Plug this value for x in the second equation:

\dfrac{a}{3}\cdot \dfrac{c-by}{a}+\dfrac{by}{2}=\dfrac{c}{6} \iff \dfrac{c-by}{3}+\dfrac{by}{2}=\dfrac{c}{6} \iff \dfrac{2(c-by)+3by}{6}=\dfrac{c}{6}

Multiply both sides by 6 to get

2(c-by)+3by=c \iff 2c-2by+3by=c \iff by=-c \iff y=-\dfrac{c}{b}

Plug this value for y in the expression for x:

x = \dfrac{c-by}{a} = \dfrac{c-b\cdot\frac{-c}{b}}{a}=\dfrac{2c}{a}

Since both a,b are not zero, both solutions are well defined.

8 0
3 years ago
Multiply. Write your answer as a fraction in simplest form.<br> 6 x 3/22
VARVARA [1.3K]
I got ya!!!,

The answer is 3/11
5 0
3 years ago
Read 2 more answers
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