Write a quadratic function with two real zeros.

1 answer:

5 0

The formula for quadratic equation is given by:

x² - (sum)x + (product) = 0

so if we have real roots of 3 and 5

<span> x² - (3 + 5)x + (3*5) = 0
</span> x² - 8<span>x + 15 = 0
</span>
so if we have real roots of -3 and -6

<span> x² - (-3 - 6)x + (-2*-6) = 0
</span> x² - (-9<span>x) + 12 = 0
</span> x² + 9<span>x + 12 = 0</span>

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2 years ago

Please explain the problem to me step by step

JulijaS [17]

<h3>Solution:</h3>

$\frac{4y}{9} - \frac{2y}{3} = 10 \\ = > \frac{4y - 6y}{9} = 10 \\ = > \frac{ - 2y}{9} = 10 \\ = > y = 10 \times \frac{9}{ - 2} \\ = > y = - 5 \times 9 \\ = > y = - 45$