Write a quadratic function with two real zeros.

1 answer:

5 0

The formula for quadratic equation is given by:

x² - (sum)x + (product) = 0

so if we have real roots of 3 and 5

 x² - (3 + 5)x + (3*5) = 0
 x² - 8x + 15 = 0

so if we have real roots of -3 and -6

 x² - (-3 - 6)x + (-2*-6) = 0
 x² - (-9x) + 12 = 0
 x² + 9x + 12 = 0

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If the atomic number is 15 how many protons will it have?

andrey2020 [161]

It will have 15 protons because the atomic number will always equal the number of protons and vice versa

6 0

2 years ago

Can someone please explain how to do these?

Pani-rosa [81]

Answer:

First question answer: The limit is 69

Second question answer: The limit is 5

Step-by-step explanation:

For the first limit, plug in $x=8$ in the expression $(9x-3)$ , that's the answer for linear equations and limits.

So we have:

$9x-3\\9(8)-3\\72-3\\69$

The answer is 69

For the second limit, if we do same thing as the first, we will get division by 0. Also indeterminate form, 0 divided by 0. Thus we would think that the limit does not exist. But if we do some algebra, we can easily simplify it and thus plug in the value $x=1$ into the simplified expression to get the correct answer. Shown below: