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3 years ago

11

Write a quadratic function with two real zeros.

1 answer:

satela [25.4K]3 years ago

5 0

The formula for quadratic equation is given by:

x² - (sum)x + (product) = 0

so if we have real roots of 3 and 5

<span> x² - (3 + 5)x + (3*5) = 0
</span> x² - 8<span>x + 15 = 0
</span>
so if we have real roots of -3 and -6

<span> x² - (-3 - 6)x + (-2*-6) = 0
</span> x² - (-9<span>x) + 12 = 0
</span> x² + 9<span>x + 12 = 0</span>

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<h2>Answer:</h2>

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3 years ago

Read 2 more answers

Find for x<br><br> 1/5x + 1/3= 3(2/3x -2)

topjm [15]

Answer:

The value of x for the given expression is (95/27)

Step-by-step explanation:

Here, the given expression is:

$\frac{1}{5} x + \frac{1}{3} = 3(\frac{2}{3}x -2)$

Now here solving for the value of x , we get

$\frac{1}{5} x + \frac{1}{3} = 3(\frac{2}{3}x) -6\\\implies\frac{1}{5} x + \frac{1}{3} = 2x -6$

Now, taking the variable terms on 1 side, we get

$\frac{1}{5} x - 2x = -6 - \frac{1}{3} \\\implies\frac{x - 10x}{5} = -(\frac{6(3) +1}{3} )$

or, $\frac{-9x}{5} = -\frac{19}{3} \implies x = \frac{19}{3} \times\frac{5}{9} = \frac{95}{27}$

Hence, the value of x = (95/27)

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3 years ago