There is a fire in the third floor of a building, 22 feet above the ground. The fire truck has a 16-foot tall ladder on top, and
the truck itself is 6 feet tall. The angle of the ladder with the top of the truck is 75°. Will the ladder reach the fire.
1 answer:
Answer: Yes the ladder will reach the fire
Step-by-step explanation: Please refer to the attached diagram for details.
The fire is at point A, while the top of the truck is at point C. The fire is actually burning at 22 feet off the ground, but because the fire truck itself is already 6 feet off the ground, the point that would serve as the base of the building would be 16 feet from the third floor (which is 22 feet minus 6 feet). Hence, point A to point B is 16 feet. So we need to calculate if line AC (from the truck to the fire at the third floor, labeled as b) shall equal the length of the ladder which is 16-foot long.
The angle of the ladder with the top of the truck is 75 degrees. Therefore,
Sin 75 = opposite/hypotenuse
Sin 75 = 16/b
By cross multiplication we now have
b = 16/Sin 75
b = 16/0.9659
b = 16.56
If the distance from A to C is 16.56 feet, then the 16-foot long ladder would reach the fire.
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Step-by-step explanation:
From image we get a graphical representation of the second-order polynomial , where
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a)
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,
b)
There are two approximate solutions according to the graph, which are marked by red circles in the image attached below:
,
Answer:
x = ±
Step-by-step explanation:
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The first step is to subtract 50 from both sides of the equation;
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Answer:
The coordinates of the endpoints of the side congruent to side EF is:
E'(-8,-4) and F'(-5,-7).
Step-by-step explanation:
<em>" when point M (h, k) is rotated about the origin O through 90° in anticlockwise direction or we can say counter clockwise. The new position of point </em><em>M (h, k) will become M' (-k, h) "</em>
We are given a trapezoid such that the vertices of trapezoid are:
E(-4,8) , F(-7,5) , G(-4,3) , H(-2,5)
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E(-4,8) → E'(-8,-4)
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H(-2,5) → H'(-5,-2)
Hence the coordinates of the endpoints of the side congruent to side EF is:
E'(-8,-4) and F'(-5,-7).
