Answer:
Answer:
safe speed for the larger radius track u= √2 v
Explanation:
The sum of the forces on either side is the same, the only difference is the radius of curvature and speed.
Also given that r_1= smaller radius
r_2= larger radius curve
r_2= 2r_1..............i
let u be the speed of larger radius curve
now, \sum F = \frac{mv^2}{r_1} =\frac{mu^2}{r_2}∑F=
r
1
mv
2
=
r
2
mu
2
................ii
form i and ii we can write
v^2= \frac{1}{2} u^2v
2
=
2
1
u
2
⇒u= √2 v
therefore, safe speed for the larger radius track u= √2 v
Answer: The answer would be the one going a slope downwards
Step-by-step explanation:
Answer:
9,11
Step-by-step explanation:
let the numbers be x, x+2 (since consecutive odd integers have a difference of 2)
therefore;
x(x+2)= 99
x²+2x=99
I usually solve the sum like this,
we need to find the nearest square number ( number smaller than the number on the R.H.S)
here, it is 81, whose square root is 9. therefore the solution is 9
verification:
(9)²+2*9=99
81+18=99
99=99
hence, 9 is the solution. therefore the positive odd consecutive integers are
x=9
x+2=9+2= 11
verification:
9*11=99
99=99
L.H.S=R.H.S
Answer:
it's like 12 because 12 over the 4 get to 40 minus 12
Answer:
0.82
Step-by-step explanation:
The question says that three percent (3 out of 100) of the rackets (racquets) produced by the company are found to be defective.
First thing to calculate is the probability that 1 in a box of 6 rackets are defective.
That probability is gotten by cross multiplying, as illustrated below;
3 - 100
x - 6
x = (6×3)/100 = 18/100 = 0.18
Since the probability of having/finding 1 defective racket in a box of 6 is 0.18, the probability of finding more than 1 (minimum of 2 and maximum of all six) defective rackets in same box would be (1 - 0.18) = 0.82
