Answer:
-4 + -6 = -10
Step-by-step explanation:
From the line at negative 4 it goes to negative 10 you need to add six to four to make ten. Though since it is negative numbers we add a negative 6
Hello, how is your day? :)
Answer:
B. 1 out of 5,005
Step-by-step explanation:
Given
Number of Friends = 15
Required
Probability of selecting 6 friends
The first step is to calculate the number of ways 6 friends can be selected
The keyword in the above statement is selection;
This implies combination;
The number of ways is calculated as follows;
![\left[\begin{array}{c}n&r&\end{array}\right] = \frac{n!}{(n-r)!r!}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dn%26r%26%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7Bn%21%7D%7B%28n-r%29%21r%21%7D)
Where n = 15 and r = 6
![\left[\begin{array}{c}n&r&\end{array}\right] = \frac{n!}{(n-r)!r!}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7Dn%26r%26%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7Bn%21%7D%7B%28n-r%29%21r%21%7D)
becomes
![\left[\begin{array}{c}15&6&\end{array}\right] = \frac{15!}{(15-6)!6!}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D15%266%26%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B15%21%7D%7B%2815-6%29%216%21%7D)
![\left[\begin{array}{c}15&6&\end{array}\right] = \frac{15!}{9!6!}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D15%266%26%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B15%21%7D%7B9%216%21%7D)
![\left[\begin{array}{c}15&6&\end{array}\right] = \frac{15 * 14 * 13 * 12 * 11 *10 * 9!}{9! *6 * 5 * 4 * 3 * 2 * 1}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D15%266%26%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B15%20%2A%2014%20%2A%2013%20%2A%2012%20%2A%2011%20%2A10%20%2A%209%21%7D%7B9%21%20%2A6%20%2A%205%20%2A%204%20%2A%203%20%2A%202%20%2A%201%7D)
![\left[\begin{array}{c}15&6&\end{array}\right] = \frac{15 * 14 * 13 * 12 * 11 *10}{6 * 5 * 4 * 3 * 2 * 1}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D15%266%26%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B15%20%2A%2014%20%2A%2013%20%2A%2012%20%2A%2011%20%2A10%7D%7B6%20%2A%205%20%2A%204%20%2A%203%20%2A%202%20%2A%201%7D)
![\left[\begin{array}{c}15&6&\end{array}\right] = \frac{3603600}{720}](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D15%266%26%5Cend%7Barray%7D%5Cright%5D%20%3D%20%5Cfrac%7B3603600%7D%7B720%7D)
![\left[\begin{array}{c}15&6&\end{array}\right] =5005](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Bc%7D15%266%26%5Cend%7Barray%7D%5Cright%5D%20%3D5005)
Hence, there are 5005 ways of selecting 6 from 15 friends
Since, there's only one way of selecting the 6 named friends
Then, the probability is 1 out of 5,005
I can’t read it clearly but since he spinned it it prolly had something to do with rotation
Multiply the GCF of the numerical part 3 and the GCF of the variable part x^2y to get
3x^2y.