Question

Tower A is 20 miles due North of tower B. A dinosaur is spotted from the tower A at °E and from tower Bat N34°E. How far is the dinosaur from tower B?

Answer 1

Answer:

Step-by-step explanation:

let dinosaur be at C

apply sine formula

∠A=56°

∠B=34°

∠C=180-(56+34)=180-90=90°

$\frac{20}{sin 90} =\frac{BC}{sin 56} \\BC=20 sin 56 \approx 16.58 miles$