Answer:
8:30
Step-by-step explanation:
Because 6 ÷ 4 is 1.5. also know as 1.5hrs before bedtime.
After plotting the quadrilateral in a Cartesian plane, you can see that it is not a particular quadrilateral. Hence, you need to divide it into two triangles. Let's take ABC and ADC.
The area of a triangle with vertices known is given by the matrix
M =
![\left[\begin{array}{ccc} x_{1}&y_{1}&1\\x_{2}&y_{2}&1\\x_{3}&y_{3}&1\end{array}\right]](https://tex.z-dn.net/?f=%20%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7D%20x_%7B1%7D%26y_%7B1%7D%261%5C%5Cx_%7B2%7D%26y_%7B2%7D%261%5C%5Cx_%7B3%7D%26y_%7B3%7D%261%5Cend%7Barray%7D%5Cright%5D%20)
Area = 1/2· | det(M) |
= 1/2· | x₁·y₂ - x₂·y₁ + x₂·y₃ - x₃·y₂ + x₃·y₁ - x₁·y₃ |
= 1/2· | x₁·(y₂ - y₃) + x₂·(y₃ - y₁) + x₃·(y₁ - y₂) |
Therefore, the area of ABC will be:
A(ABC) = 1/2· | (-5)·(-5 - (-6)) + (-4)·(-6 - 7) + (-1)·(7 - (-5)) |
= 1/2· | -5·(1) - 4·(-13) - 1·(12) |
= 1/2 | 35 |
= 35/2
Similarly, the area of ADC will be:
A(ABC) = 1/2· | (-5)·(5 - (-6)) + (4)·(-6 - 7) + (-1)·(7 - 5) |
= 1/2· | -5·(11) + 4·(-13) - 1·(2) |
= 1/2 | -109 |
<span> = 109/2</span>
The total area of the quadrilateral will be the sum of the areas of the two triangles:
A(ABCD) = A(ABC) + A(ADC)
= 35/2 + 109/2
= 72
Hello!
To write this equation we will use c to represent the total cost, and g to represent however many games you download.
c=12.49+0.99g
The constant rate is 12.49, that will never increase or change in our equation.
Depending on how many games you download, that will be the rate that affects our total cost.
If you only purchase one game, you only spend $13.48. Where as if you buy 10 games, you spend $22.39.
Answer:
1539 cubic meters
Step-by-step explanation:
Hello, I can help you with this
to solve need we will need these two equations
Step one
Remember
area of a circle

Also, the volume of the cylinder
Volume= area of the circle * height

Step 2
put the values into the equation
Let
diameter= 14 m
height = 10 m

I hope it helps,have a great day.
Answer:
Line 1 to Line 2: Distributive Property
Line 2 to Line 3: Commutative Property of Multiplication
Line 3 to Line 4: Associative Property of Multiplication
Step-by-step explanation: