2x≥12 I can't figure this out

Mathematics

2 answers:

Serhud [2]2 years ago

7 0

Answer:

$x \geq 6$

Step-by-step explanation:

You can start by dividing both sides by 2, getting $x \geq 6$ .

JulijaS [17]2 years ago

3 0

Answer:

Step-by-step explanation:

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1. What is the factored form of q2 - 12q + 36? (1 point)

Novay_Z [31]

Step-by-step explanation:

${q}^{2} - 12q + 36 \\ = {q}^{2} - 6q - 6q + 36 \\ = q(q - 6) - 6(q - 6) \\ \huge \red{ \boxed {= (q - 6)(q - 6) }}\\ is \: the \: factored \: form.$

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3 years ago

Pls help trig question!!

s2008m [1.1K]

$4\sin^2 x - 3 = 3 \sin x\\\\\implies 4\sin^2 x -3 \sin x -3 =0\\\\\implies 4u^2 -3u -3 =0~~~~~~~~~~~~~~;[\text{Set} ~ \sin x = u]\\\\\implies u = \dfrac{-(-3) \pm \sqrt{(-3)^2 - 4\cdot 4 \cdot (-3)}}{2(4)}~~~~~~;[\text{Apply quadratic formula}]\\\\\\\implies u = \dfrac{3\pm\sqrt{57}}8\\\\\implies \sin x = \dfrac{3\pm\sqrt{57}}8~~~~~~;[\text{Substitute back}~ u = \sin x]\\\\\text{Now,}\\\\\sin x = \dfrac{3+\sqrt{57}}8\\\\\text{No solution for}~ x\in \mathbb{R} ~\text{Since}~ -1\leq \sin x \leq 1\\$

$\sin x = \dfrac{3 - \sqrt{57}}8\\\\\implies x = n\pi + (-1)^n \sin^{-1} \left(\dfrac{3-\sqrt{57}}8\right)\\\\\\\text{ When n = 1,2 and}~ [0,2\pi]},\\\\\\x= \pi - \sin^{-1} \left(\dfrac{3-\sqrt{57}}8 \right)~ \text{and} ~x = 2\pi + \sin^{-1} \left(\dfrac{3-\sqrt{57}}8 \right)\\\\\text{In decimal,}\\\\x= 3.75~~~~ \text{and}~~~ x =5.68$