What kind of energy transfer
<em>K</em> = 2.4 × 10^(-72)
<em>Step 1</em>. Determine the <em>value of n
</em>
Zn^(2+) + 2e^(-) → Zn
2Cl^(-) → Cl_2 + 2e^(-)
Zn^(2+) + 2Cl^(-) → Zn + Cl_2
∴ <em>n</em> = 2
<em>Step 2</em>. Calculate <em>K</em>
log<em>K</em> = <em>nE</em>°/0.0592 V = [2 × (-2.12 V)]/0.0592 V = -71.62
<em>K</em> = 10^(-71.62) = 2.4 × 10^(-72)
Answer:
FAS concentration = 1.61*10^-4M
Explanation:
Beer Lambert's law relates the absorbance (A) of a substance to its concentration (c) as:

where ε = molar absorption coefficient
l = path length
A plot of 'A' vs 'c' gives a straight line with slope = εl
In addition absorbance (A) is related to % Transmittance (%T) as:
A = 2-log%T----(2)
For the FAS solution, the corresponding calibration fit is given as:
y = 3678(x) + 0.056
This implies that the slope = εl = 3678
It is given that %T = 25.6%

Based on equation(1):

I don't know which one I should answer