Answer:
Ok so I dont have a paper on me, but to solve this, first you need to know, 1 ml is 1 cubic centimeter, okay so we need to find the volume, which is 4/3 times pie times r cubed, the answer to this equation will then bet 51 cubic centimeters which directly translate to 51 ml pushed out of the full cup
In a solution, when the concentrations of a weak acid and its conjugate base are equal: 1. the -log of the concentration of H+ and the -log of the Ka are equal.
<h3>What are Strong acid strong bases ?</h3>
Any acid that entirely ionises in solutions is considered a strong acid. When positioned, it emits the most hydrogen ions or protons.
- It is a substance with the capacity to take a proton out of an extremely weak acid. In water, they can also entirely separate into its ions. Examples include sodium hydroxide and potassium hydroxide (KOH) (NaOH)
<h3>What are weak acid and weak bases ?</h3>
Acids that don't entirely dissociate in solution are referred to as weak acids. In other words, any acid that is not a strong acid qualifies as a weak acid. The amount of dissociation determines how strong an acid is; the more dissociation, the stronger the acid.
- Weak bases are basic compounds that, when dissolved in solutions, do not entirely separate into their constituent ions.
Learn more about Acids and bases here:
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Answer:
C: metals donate electrons to non metals
Explanation:
Answer:
Kp is 0.00177
Explanation:
We state the equilibrium:
CO(g) + Cl₂(g) ⇆ COCl₂(g)
Initially we have these partial pressures
1.86 atm for CO and 1.27 for chlorine.
During the reaction, x pressure has been converted. As we have 0.823 atm as final pressure in the equilibrium for COCl₂, pressure at equilibrium for CO and chlorine will be:
1.86 - x for CO and 1.27 - x for Cl₂.
And x is the pressure generated for the product, because initially we don't have anything from it. So pressure in equilibrium for the reactants will be:
1.86 - 0.823 = 1.037 atm for CO
1.27 - 0.823 = 0.447 atm for Cl₂
Let's make, expression for Kp:
Partial pressure in eq. for COCl₂ / P. pressure in eq. for CO . P pressure in eq. for Cl₂
Kp = 0.823 / (1.037 . 0.447) → 0.00177
Flammability = A
Toxicity = D
Malleability = C
Heat of Combustion = B
