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sergiy2304 [10]
3 years ago
12

Which dissolved first in acetone? food coloring or liquid paint?​

Chemistry
1 answer:
Viefleur [7K]3 years ago
3 0

Answer:

Liquid paint.

Explanation:

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How many electrons would be exchanged from lithium and fluorine
Vikki [24]
Fluorine - Seven electrons of it's own. 

Lithium would give up one electron, so there for, fluorine is then left with eight.
3 0
3 years ago
Does anyone have answers of a worksheet called “ Intro to Graphs” Chemquest 2?
r-ruslan [8.4K]

Answer:

no

Explanation:

Because I have lost and I dont know where is the worksheet

8 0
2 years ago
NH3 is nitrogen trihydride (ammonia) and BF3 is boron trifluoride. What is the name for AlCl3 and why?
Korvikt [17]
The answer is A. Aluminum Chloride it does not have the prefix "tri-" since it is ionic.
5 0
3 years ago
This means that if there are 15.0 g of starting chemicals, also known as
Serggg [28]

Answer:

Reactants

Explanation:

"Starting chemicals", the substances present before a reaction occurs, are called reactants.

The results of the reaction are called products, which you would also have 15.0g.

4 0
2 years ago
Draw the structure of a compound of molecular formula C4H8O that has a signal in its 13C NMR spectrum at ≥ 160 ppm. Then draw th
-Dominant- [34]

Answer:

1. Butyraldehyde; 2. but-3-en-1-ol

Explanation:

1. Peak ≥ 160 ppm

The formula C₄H₈O shows that the Index of Hydrogen Deficiency = 1.

It could be caused by either a ring or a double bond.

A peak at ≥ 160 ppm strongly indicates a C=O group, so the rest of the molecule can contain no rings or double bonds.

There are no other heteroatoms, so the compound most be an aldehyde or a ketone.

One compound that meets these criteria is butyraldehyde, CH₃CH₂CH₂CH=O (see Fig. 1.)

2. No rings; all peaks < 160 ppm

If all peaks are < 160 ppm, there can no C=O group.

There is no ring, so there must be a C=C double bond.

There is no other unsaturation, so the O atom must be present as an alcohol or an ether.

One compound that meets these criteria is but-3-en-1-ol, CH₂=CHCH₂CH₂OH (see Fig. 2).

4 0
2 years ago
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