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Zina [86]
2 years ago
11

Which moon phase comes before the phase in this picture?

Physics
2 answers:
hodyreva [135]2 years ago
8 0
Waxing gibbous
Ushjdjsidjnd
mafiozo [28]2 years ago
3 0
Waxing gibbous moon phase
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What is the total energy equation?
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The total energy equation would be Kinetic energy+Potential energy
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A fixed-geometry supersonic inlet starts at a Mach number of 3. After starting, the cruise Mach number is 2, and the operating s
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Explanation: see attachment below

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A family drives north for 30km then turns east for 20km. The family then decided to turn west for 5km before finally stopping to
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A

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Hope this helps!

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If an object were released in space far away from planted or stars and given an initial momentum, describe what would happen to
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7 0
3 years ago
Read 2 more answers
Charge A and charge B are 3.00 m apart, and charge A is +1.44 C and charge B is +3.10 C. Charge C is located between them at a c
Sidana [21]

Answer:

the distance from charge A to C is r₁₃= 1.216 m

Explanation:

following Coulomb's law , the force exerted by 2 point charges between themselves is:

F= k*q₁*q₂/r₁₂² , where q is charge , r is distance and 1 and 2 represents the charge A and charge B respectively , k=constant

since C ( denoted as 3) is at equilibrium

F₁₃=F₂₃

k*q₁*q₃/r₁₃²=k*q₂*q₃/r₂₃²

q₁/r₁₃²=q₂/r₂₃²

r₁₃²/q₁=r₂₃²/q₂

r₂₃=r₁₃*√(q₂/q₁)

since C is at rest and is co linear with A and B ( otherwise it would receive a net force in either vertical or horizontal direction) , we have

r₁₃+r₂₃=d=r₁₂

r₁₃+r₁₃*√(q₂/q₁)=d

r₁₃*(1+√(q₂/q₁))=d

r₁₃=d/(1+√(q₂/q₁))

replacing values

r₁₃=d/(1+√(q₂/q₁)) = 3.00 m/(1+√(3.10 C/1.44 C)) = 1.216 m

thus the distance from charge A to C is r₁₃= 1.216 m

7 0
2 years ago
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