Answer:
<em>a. 4.21 moles</em>
<em>b. 478.6 m/s</em>
<em>c. 1.5 times the root mean square velocity of the nitrogen gas outside the tank</em>
Explanation:
Volume of container = 100.0 L
Temperature = 293 K
pressure = 1 atm = 1.01325 bar
number of moles n = ?
using the gas equation PV = nRT
n = PV/RT
R = 0.08206 L-atm-![mol^{-1}](https://tex.z-dn.net/?f=mol%5E%7B-1%7D)
![K^{-1}](https://tex.z-dn.net/?f=K%5E%7B-1%7D)
Therefore,
n = (1.01325 x 100)/(0.08206 x 293)
n = 101.325/24.04 = <em>4.21 moles</em>
The equation for root mean square velocity is
Vrms = ![\sqrt{\frac{3RT}{M} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B3RT%7D%7BM%7D%20%7D)
R = 8.314 J/mol-K
where M is the molar mass of oxygen gas = 31.9 g/mol = 0.0319 kg/mol
Vrms =
= <em>478.6 m/s</em>
<em>For Nitrogen in thermal equilibrium with the oxygen, the root mean square velocity of the nitrogen will be proportional to the root mean square velocity of the oxygen by the relationship</em>
= ![\sqrt{\frac{Mnit}{Moxy} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7BMnit%7D%7BMoxy%7D%20%7D)
where
Voxy = root mean square velocity of oxygen = 478.6 m/s
Vnit = root mean square velocity of nitrogen = ?
Moxy = Molar mass of oxygen = 31.9 g/mol
Mnit = Molar mass of nitrogen = 14.00 g/mol
= ![\sqrt{\frac{14.0}{31.9} }](https://tex.z-dn.net/?f=%5Csqrt%7B%5Cfrac%7B14.0%7D%7B31.9%7D%20%7D)
= 0.66
Vnit = 0.66 x 478.6 = <em>315.876 m/s</em>
<em>the root mean square velocity of the oxygen gas is </em>
<em>478.6/315.876 = 1.5 times the root mean square velocity of the nitrogen gas outside the tank</em>
The longer you continue to listen, the more beats will be heard.
They'll occur at the rate of (260Hz - 254Hz) = 6 Hz .
Answer
given,
current (I) = 16 mA
circumference of the circular loop (S)= 1.90 m
Magnetic field (B)= 0.790 T
S = 2 π r
1.9 = 2 π r
r = 0.3024 m
a) magnetic moment of loop
M= I A
M=![16 \times 10^{-3} \times \pi \times r^2](https://tex.z-dn.net/?f=16%20%5Ctimes%2010%5E%7B-3%7D%20%5Ctimes%20%5Cpi%20%5Ctimes%20r%5E2)
M=![16 \times 10^{-3} \times \pi \times 0.3024^2](https://tex.z-dn.net/?f=16%20%5Ctimes%2010%5E%7B-3%7D%20%5Ctimes%20%5Cpi%20%5Ctimes%200.3024%5E2)
M=![4.59 \times 10^{-3}\ A m^2](https://tex.z-dn.net/?f=4.59%20%5Ctimes%2010%5E%7B-3%7D%5C%20A%20m%5E2)
b) torque exerted in the loop
![\tau = M\ B](https://tex.z-dn.net/?f=%5Ctau%20%3D%20M%5C%20B)
![\tau = 4.59 \times 10^{-3}\times 0.79](https://tex.z-dn.net/?f=%5Ctau%20%3D%204.59%20%5Ctimes%2010%5E%7B-3%7D%5Ctimes%200.79)
![\tau = 3.63 \times 10^{-3} N.m](https://tex.z-dn.net/?f=%5Ctau%20%3D%203.63%20%5Ctimes%2010%5E%7B-3%7D%20N.m)
Answer:
The Northern flowing stream will affect the coast of Europe by making climate of Western Europe and Northern Europe to be warmer than other areas that are located around the same latitude and this is simply because of the North Atlantic Current
Explanation:
The Northern flowing stream will affect the coast of Europe because the North Atlantic current causes the Gulf stream to be split into two ( 2 ) and the Northern stream which is a warm stream crossing over to Northern Europe. <em>The Gulf stream makes climate of Western Europe and Northern Europe to be warmer than other areas that are located around the same latitude and this is simply because of the North Atlantic Current</em>