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lora16 [44]
3 years ago
11

Two planes approach each other head on. Each has a speed of 721km/h and they spot each other when they are initially 14.7km apar

t. How many seconds (s) do the pilots have to take evasive action?
Physics
1 answer:
Naya [18.7K]3 years ago
5 0

Answer:

The time the pilots have to take evasive action is approximately 36.699 seconds

Explanation:

The direction of the planes = Towards each other

The speed of each plane, v₁, v₂ = 721 km/h

The initial distance between the two planes, d = 14.7 km

The relative velocity of the two planes, v = v₁ + v₂

v = 721 km/h + 721 km/h = 1,442 km/h

The time it will take the planes to meet, t = d/v

∴ t = 14.7 km/(1,442 km/h) = (21/2,060) h × 60 min/hr × 60 s/min ≈ 36.699 s

The time it will take the planes to meet = The time the pilots have to take evasive action, t ≈ 36.699 seconds.

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Answer:

CSP

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8 0
2 years ago
1. A 1000 kg equipment lift travels up a 200 m shaft in 45 seconds. Assuming the speed is constant, what is the
ANTONII [103]

Answer:

43,555 W

Explanation:

Since the speed is constant, this means that the force applied to lift the equipment is equal to the weight of the equipment. So we can write:

F=mg

where

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g=9.8 m/s^2 is the acceleration due to gravity

So,

F=(1000)(9.8)=9800 N

Then the work done in lifting the equipment is:

W=Fd

where

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Substituting,

W=(9800)(200)=1.96\cdot 10^6  J

Finally, the power used to lift the equipment is the ratio between the work done and time taken:

P=\frac{W}{t}

where

W=1.96\cdot 10^6 J

t = 45 s is the time taken

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P=\frac{1.96\cdot 10^6}{45}=43,555 W

8 0
3 years ago
Need help with this please
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3 years ago
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Anyone plz help!! I need the answer of q-b !
Lady_Fox [76]
The coil is rotated rapidly in the magnetic field.
The magnetic flux linked with the coil changes and thus, an emf is induced which leads to the flow of current .

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Simora [160]

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