Answer:
1. 230 kg...
W = m * g
W= 230 kg * 9.81 m/s^2
<u>W= 2256,3 N</u>
m= 230kg , W = 2256,3 N , g= 9.81 m/s^2
2. 887 N
W= m * g
887 N = m * 9.81 m/s^2
<u>m= 90,42 kg</u>
m= 90,42 kg, W = 887 N , g= 9.81 m/s^2
3. 420 kg
W= m * a
w= 420 kg * 9.81 m/s^2
<u>w=</u><u> </u><u>4120,2 N</u>
m= 420 kg , W = 4120,2 N , g= 9.81 m/s^2
4. Determine the gravity on Pluto where a 15 kg object weighs 55.5N.
w = m * g
55.5 N = 15 kg * g
<u>a= 3,7 m/s^2</u>
m = 15 kg , W= 55.5 N , g= 3,7 m/s^2
Cell membrane can also be called plasma membrane
Answer:
Explanation:
Answer: Let ke = 1/2 IW^2 = 1/2 kMr^2 W^2 be Earth's rotational KE. W = 2pi/24 radians per hour rotation speed and k = 2/5 for a solid sphere M is Earth mass, r = 6.4E6 m.
Then ke = 1/2 2/5 6E24 (6.4E6)^2 (2pi/(24*3600))^2 = ? Joules. You can do the math, note W is converted to radians per second for unit consistency.
Let KE = 1/2 KMR^2 w^2 be Earth's orbital KE. w = 2pi/(365*24) radians per hour K = 1 for a point mass. Note I used 365 days, a more precise number is 365.25 days per year, which is why we have Leap Years.
Find KE/ke = 1/2 KMR^2 w^2//1/2 kMr^2 W^2 = (K/k)(w/W)^2 (R/r)^2 = (5/2) (365)^2 (1.5E11/6.4E6)^2 = 7.81E9 ANS
Answer:
Explanation:
Angular velocity of satellite
= 2π x .01
= .02 π rad /s
Initial angular momentum
Moment of inertia x angular velocity
= 2000 x .02 π
= 125.6 unit
Linear impulse produced by each thruster
= 15 N.s
Angular impulse
= 15 x 1.5 = 22.5 unit
Total angular impulse in 30 pulses
= 22.5 x 2 x 30
1350
This angular impulse will add total angular momentum of
1350 unit
So total angular momentum after 30 pulses
= 1350 + 22.5
= 1372.5 unit
So final angular velocity
= final angular momentum / moment of inertia
= 1372.5 / 2000
= 0 .686 rad /s
Answer:
Current in the toroid will be 
Explanation:
We have given number of winding in rectangular toroid N = 1500
Self inductance of toroid L = 0.06 H
Magnetic energy stored in toroid 
We have to find the current in the toroid
Magnetic energy stored is equal to 


So current in the toroid will be 