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Natasha_Volkova [10]
3 years ago
11

A 25.0 g marble sliding to the right at 20.0 cm/s overtakes and collides elastically with a 10.0 g marble moving in the same dir

ection at 15.0 cm/s. after the collision, the 10.0 g marble moves to the right at 22.1 cm/s. find the velocity of the 25.0 g marble after the collision.
Physics
1 answer:
vovikov84 [41]3 years ago
6 0
In collision that are categorized as elastic, the total kinetic energy of the system is preserved such that,

   KE1  = KE2

The kinetic energy of the system before the collision is solved below.

  KE1 = (0.5)(25)(20)² + (0.5)(10g)(15)²
  KE1 = 6125 g cm²/s²

This value should also be equal to KE2, which can be calculated using the conditions after the collision.

KE2 = 6125 g cm²/s² = (0.5)(10)(22.1)² + (0.5)(25)(x²)

The value of x from the equation is 17.16 cm/s.

Hence, the answer is 17.16 cm/s. 
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Answer:

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A weight suspended from a spring is seen to bob up and down over a total distance of 20 centimeters twice each second.
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"Twice each second" means "2 per second".  <em>Frequency = 2 Hz.</em>

<em>Period </em>= time for one bounce = <em>1 second</em>

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3 years ago
What type of metal are conducting wires most often made of?<br><br> #16
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Answer:

here

Explanation:

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2 years ago
Jane's brother Andrew leaves home for school at 8:00 am. He walks at 3.3 kph. At 8:20 am Jane discovers that Andrew has left his
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An airplane flies eastward and always accelerates at a constant rate. At one position along its path it has a velocity of 34.3 m
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Explanation:

We'll need two equations.

v² = v₀² + 2a(x - x₀)

where v is the final velocity, v₀ is the initial velocity, a is the acceleration, x is the final position, and x₀ is the initial position.

x = x₀ + ½ (v + v₀)t

where t is time.

Given:

v = 47.5 m/s

v₀ = 34.3 m/s

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40100 = ½ (47.5 + 34.3)t

t = 980 s

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