CO2 , NaCl , HCl can be classified as ?

All ball is thrown up with a vertical velocity of 54 m/s and a horizontal velocity of 39 m/s. Calculate how many seconds it will

VikaD [51]

5.5 s

Explanation:

The time it takes for the ball to reach its maximum height can be calculated using

$v_y = v_{0y} - gt \Rightarrow t = \dfrac{v_{0y}}{g}$

since $v_y = 0$ at the top of its trajectory. Plugging in the numbers,

$t = \dfrac{(54\:\text{m/s})}{(9.8\:\text{m/s}^2)} = 5.5\:\text{s}$

8 0

3 years ago

Pendulum A has a bob of mass m hung from the string of length L; pendulum B is identical to A except its bob has the length 2L.

GenaCL600 [577]

Answer:

$f_{B}: f_{A} = \sqrt{\frac{2}{1}}$

Explanation:

For pendulum A: Length = L and gravity = g

The frequency of pendulum A is given by

$f = \frac{1}{2\pi }\sqrt{\frac{g}{L}}$

Here, f is the frequency, L be the length

$f_{A} = \frac{1}{2\pi }\sqrt{\frac{g}{L}}$ ... (1)

For pendulum B: Length = 2L, gravity = g

The frequency of pendulum B is given by

$f_{B} = \frac{1}{2\pi }\sqrt{\frac{g}{2L}}$ .... (2)

Divide equation (1) by (2)

$f_{B}: f_{A} = \sqrt{\frac{2}{1}}$

5 0

3 years ago

Choose all the answers that apply. Power is calculated using ___.

antiseptic1488 [7]

Time , Work, Horsepower

Explanation:

In General, Power is defined as rate of doing work in physics.

1.) By work and Time, we can calculate power as follows,

Power = Work done per unit Time

= Work done / time

2.) From Horsepower we can directly get the power.

Horsepower (hp) is a unit to measure the power, or the rate at which work is done, usually in the output of engines or motors. There are many types of horsepower. Two common ways of defining horsepower is being used today are the mechanical horsepower (or imperial horsepower), which is about 745.7 watts, and the metric horsepower, which is approximately 735.5 watts.

5 0

3 years ago

g 1. Water flows through a 30.0 cm diameter water pipe at a speed of 3.00 m/s. All of the water in the pipe flows into a smaller

levacccp [35]

Answer:

a) v₂ = 30 m/s

b) m₁ = 12600 kg

c) m₂ = 12600 kg

Explanation:

a)

Using the continuity equation:

$A_1v_1 = A_2v_2$

where,

A₁ = Area of inlet = π(0.15 m)² = 0.07 m²

A₂ = Area of outlet = π(0.05 m)² = 0.007 m²

v₁ = speed at inlet = 3 m/s

v₂ = speed at outlet = ?

Therefore,

$(0.07\ m^2)(3\ m/s)=(0.007\ m^2)v_2\\\\v_2 = \frac{0.21\ m^3/s}{0.007\ m^2}$

v₂ = 30 m/s

b)

$m_1 = \rho A_1v_1t$

where,

m₁ = mass of water flowing in = ?

ρ = density of water = 1000 kg/m³

t = time = 1 min = 60 s

Therefore,

$m_1 = (1000\ kg/m^3)(0.07\ m^2)(3\ m/s)(60\ s)\\$

m₁ = 12600 kg

c)

$m_1 = \rho A_1v_1t$

where,

m₂ = mass of water flowing out = ?

ρ = density of water = 1000 kg/m³

t = time = 1 min = 60 s

Therefore,

$m_2 = (1000\ kg/m^3)(0.007\ m^2)(30\ m/s)(60\ s)\\$

m₂ = 12600 kg

7 0

3 years ago

A student wants to draw a diagram to show the path of a light wave. Which

wariber [46]

Answer:

D

Explanation:

light moves in a straight line (sorry if I'm wrong)

8 0

3 years ago