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Elena L [17]
3 years ago
6

In a newspaper, it was reported that yearly robberies in Springfield were down 15% to 136 in 2014 from 2013. How many robberies

were there in Springfield in 2013?
Mathematics
1 answer:
podryga [215]3 years ago
4 0

Answer:

Step-by-step explanation:

To find the solution call x the yearly robberies in 2013.

We now that  

x-0.15x=135\\0.75x=135\\x=\frac{135}{0.75}

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| 9. The distance between Town A and Town B was 108 km. A car and a van left Town A at 12 00 for Town B. On reaching Town B, the
Westkost [7]

Answer:

a)  Time until both vehicles meet is 1.5 hours after starting at noon.  That makes it 1:30PM.

b)  Average speed of car is 84 km/h

Step-by-step explanation:

A -----------------------z------------B

          <u>Left</u>      <u>Speed(km/h)</u>      <u>Time</u>

Car:   12PM            X  

Van:   12PM           60

Car/Van

DistanceCar        AB + z

DistanceVan       Az

Ratio:                  (AB+z)/Az  = 7/5

Time until both meet = T (in hours)

Distance Car:            xT

Distance Van:           60T

====

  xT = AB + z

  60T = Az

---

(xT/60T)= (7/5)

x = 60(7/5)

x = 84 km/h

=====

Time for car to reach B is:    time (hr) = 108 km/(84 km/h)

                                                 time = 1.286 hours

Distance for at 1.289 hours is:    distance (km) = (60 km/h)*(1.286 h)

                                                   distance = 77.14 km

At 1.286 hours, the car reverses direction.  The van is (108 km - 77.14 km) or 30.86 km away.

Add the distances travelled by both vehicles after the car reverses direction at 1.286 hours.  The sum will be 30.86 km when they meet, at time of T.

Car Distance + Van Distance = 30.86 km

T(84 km/h) + t(60 km)

They meet when they are 0 km apart, which can be modeled with the following equation:

Van travel Distance - Car Travel Distance = 0 starting at 1.286 hr.

Let <u>t</u> be the time <u>after</u> 1.286 hours that both vehicles meet/collide.

t*(60 km/h)  +  t(84 km/h) = 30.86 km

t(60+84) = 30.86 km

t(144 km/h) = 30.86 km

t = 0.2143 hr

Total time until the car and van meet is 1.286 hr + 0.2143 hr for a total of 1.50 hours.

=================

a)  Time until both vehicles meet is 1.5 hours after starting at noon.  That makes it 1:30PM.

b)  Average speed of car is 84 km/h

==============

<u>CHECK</u>

Is the ratio of the distance travelled by the car and the van until they meet in the ratio of 7/5?

Car distance is (1.5 hr)(84 km/h) = 126 km

Van distance is (1.5 hr)(60 km/h) = 90.0 km

Ratio is 126/90 or 1.4

Ratio of 7/5 is 1.4

<u><em>YES</em></u>

     

3 0
2 years ago
URGENT !!!!!!!!!!!! Please answer correctly !!!!!!!!! Will<br> Mark Brianliest !!!!!!!!!!!!!!!!
mina [271]

Answer:

MLH is congruent to JKI

LNK is congruent to HNI

I think that's how you're supposed to answer it...

3 0
3 years ago
Could someone help me with these 2 questions
Lunna [17]
∠P~=∠S
∠Q ~= ∠T
∠R~= ∠M
P/S=Q/T=RM
hope this helps!
4 0
3 years ago
Please helppp why is he right or wrong!!
bagirrra123 [75]

Answer:

We cannot agree with Andre because x = 3.

Step-by-step explanation:

Assuming the diagram is a weighing scale which can also be represented as an equation having two sides that is balanced. We can express the situation as follows using equation:

x + 2 = 5

Solve for x

x + 2 - 2 = 5 - 2 (subtraction property of equality)

x = 3

If you plug in the value of x on the diagram given, the scale becomes balance on each side.

Therefore, x = 3. Andre is wrong and we cannot agree with Andre.

7 0
3 years ago
3/8 + 3/4 in simplest form
zalisa [80]

Answer:

1 and 1/8

Step-by-step explanation:

turn 3/4 times 2 and you get 6/8 then you add it

I hope I helped!

4 0
3 years ago
Read 2 more answers
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