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Vsevolod [243]
3 years ago
14

A particle of charge +13 µC and mass 3.57 10-5 kg is released from rest in a region where there is a constant electric field of

+495 N/C. What is the displacement of the particle after a time of 1.50 10-2 s?
Physics
1 answer:
DerKrebs [107]3 years ago
8 0

Answer:

20.3 mm

Explanation:

The force  on the charge F = qE where q = charge = +13 µC = +13 × 10⁻⁶ C and E = electric field intensity = +495 N/C.

The acceleration of the charge is thus a = F/m where m = mass of charge = 3.57 × 10⁻⁵ kg.

Its displacement is gotten from

s = ut + at²/2  where u = initial speed = 0 (since the charge starts from rest) and t = 1.5 × 10⁻² s.

s = 0 +at²/2 = at²/2

Substituting a and t into s we have

s = qEt²/2m = +13 × 10⁻⁶ C × +495 N/C × (1.5 × 10⁻² s)²/(2 × 3.57 × 10⁻⁵ kg) = 0.0203 m = 20.3 mm

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Kinetic energy is energy of motion.

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If there's any wind, then air is moving. The moving air has kinetic energy.

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Calculate the amount of energy transferred when a 40w light bulb is left on for 30 minutes.
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Explanation:

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In the heat equation what does Q represent
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Q stands for heat energy (Joules) hope this helps!
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Wondering if you have enough rope to rappel to the ground, you drop a rock off the top, and hear the sound of it hitting the bot
miskamm [114]

Answer:

86.5 m

Explanation:

s =  ut +  \frac{1}{2} at {}^{2}  \\ s = (0)(4.2) +  \frac{1}{2} (9.81)(4.2) {}^{2} \\ s = 86.5m

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3 years ago
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Two uniform spheres,each of mass 0.260kg are fixed at points A and B
Ivan

Answer:

a) 2.76x10^-9 m/s^2

b) downward

Explanation:

a) In order to do this, we need to use the newton's law of gravitation which is:

F = G.m/r²

Where:

G: Constant of gravitation (6.67x10^-11 N/m)

m: mass of the object

r: distance or radius of the object.

In this case, we have two spheres, so this law becomes:

F = G*m1*m2 / r²

Now, you are not providing a picture with this, however, this problem is very similar to one I solved before, so, I'm gonna use the same values to solve this. If, you have different values for the distance, just replace them in this procedure and should get the correct and more accurate answer.

In this case, the distance that separates sphere in P from sphere A and B is 10 cm. As both spheres have the same mass and they are at the same distance from P, we can assume that F1 = F2 so:

F1 = (6.67x10^-11) * (0.01) * (0.26) / (0.1)² = 1.73x10^-11 N

sphere at P, will roll downward to the middle of sphere A and B. The distance between these two points it's 8 cm (See picture attached)

Now, according to my data, they are exerting a force in the y axis, so:

F1y = Fy * senФ

senФ using trigonometry is:

senФ = opposite lenght / hipotenuse

senФ = 8/10 = 0.8

Replacing:

F1y = 1.73x10^-11 * 0.8 = 1.38x10^-11 N

This force it's exactly the same as F2y, so the total force is:

F = 1.38x10^-11 * 2 = 2.76x10^-11 N

Finally, using the second law of Newton:

F = m*a

Solving for a:

a = F/m

replacing:

a = 2.76x10^-11 / 0.01

a = 2.76x10^-9 m/s²

According to the picture and the value of this magnitude, it's going downward.

3 0
3 years ago
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